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3 years ago

Shown below is a parallel circuit of two light bulbs.

1 answer:

3 0

The characteristics of parallel circuits allow to find the correct answer for the question about what happens when a light bulb is:

D) Bulb 2 will stay lit and the light source will be stronger.

Electrical circuits have two forms and connection:

• Serie. In this case there is only one path through which current can circulate the current.

• Parallel. There are several roads where the current can circulate.

In a parallel circuit, the total current in the circuit is the sum of the current in each branch, the voltage in all branches remains constant.

Let's analyze the claims:

A) False. The bulbs are independent, what happens to one does not affect the other.

B) False. Both bulbs were on, so the second bulb should not be affected.

C) False. When burn a light bulb, there is more current in the other branch, The opposite happens.

D) True. When burn a light bulb there is more current in the other branch and therefore the light bulb 2 can dissipate more power by shining a little brighter.

In conclusion, using the characteristics of parallel circuits we can find that the correct answer for the question about what happens when a light bulb burns out is:

D) Bulb 2 will stay lit and the light source will be stronger.

Learn more about parallel circuits here: brainly.com/question/23088951

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Answer:

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Explanation:

The photoelectric effect was explained by Eintein assuming that the light was made up of particles called photons and these collided with the electrons taking them out of the material.

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where K is the kinetic energy of the ejected electrons, hf is the energy of the light quanta and fi is the work function of the material.

The speed of light is related to wavelength and frequency

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for the case that they ask us the kinetic energy of the electons is zero (K = 0)

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3 years ago

If the range of a projectile's trajectory is six times larger than the height of the trajectory, then what was the angle of laun

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Answer:

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H = 1/8 g T^2 where T is total time in air (2 t = T)

R = V T cos θ horizontal range

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cos θ = 3 g T / (4 V) (I)

Now t = V sin θ / g time for projectile to fall from max height

T = 2 V sin θ / g

T / V = 2 sin θ / g

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