1. Write down the readings on the side of Figs. 6 (a), (b) and (c) respectively. What is the least count of instrument scale for
each of the three measurement tools? Fig. 6 (a) Meterstick (cm)
Fig. 6 (b) Vernier Caliper (cm)
Fig. 6 (c) Micrometer (mm)
2. What is the difference between the measured values 1.05 m and 1.050 m? What factor of a
measurement tool determines the significant figures of a measured value?
Fig. 6 (b) Vernier Caliper (cm)
Fig. 6 (c) Micrometer (mm)
2. What is the difference between the measured values 1.05 m and 1.050 m? What factor of a
measurement tool determines the significant figures of a measured value?
1 answer:
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Answer:
Explanation:
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Answer:
The length of the longer pipe is L = 2.30 m
Explanation:
Given that:
Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.
How long is the other pipe?
From above;
The formula for the frequency of open ended pipes can be expressed as:
where n = 1 ( since half wavelength exist between those two pipes)
v = 343 m/s and L = 2.08 m
Thus, the shorter pipe produces a frequency of :
Also; we know that the beat frequency was given as 8.0 Hz
Then,
The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz
The lower frequency of the longer pipe = 74.45 Hz
Finally;
From the above equation; make Length L the subject of the formula. Then,
The length of the longer pipe is L =
The length of the longer pipe is L =
The length of the longer pipe is L =
The length of the longer pipe is L = 2.30 m