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kifflom [539]
4 years ago
9

If acid is splashed on your lab partner, immediately do which of the following?

Chemistry
2 answers:
Dima020 [189]4 years ago
8 0
C. because it will hopefully cleanse them of the acid
amid [387]4 years ago
5 0
Well really the right thing to do is find the nearest shower and rinse them off so I believe C. would be the best answer
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Calculate the energy required to heat of 1.50 kg silver from -7.8 C to 15.0 C . Assume the specific heat capacity of silver unde
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Answer:

804 J

Explanation:

Step 1: Given data

  • Mass of silver (m): 1.50 kg
  • Initial temperature: -7.8 °C
  • Final temperature: 15.0 °C
  • Specific heat capacity of silver (c): 0.0235J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.0235J·g⁻¹K⁻¹ × (1.50 × 10³g) × [15.0°C-(-7.8°C)]

Q = 804 J

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3 years ago
A _______ reaction involves burning. this reaction requires energy to start, but it releases more energy then is required to sta
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The answer is combustion
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Tire manufacturers design tires to stop quickly in various conditions. Use the table to answer the question: Which tire would be
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Can you show the picture?


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What is the density of a substance that has a mass of 20 g and a volume of<br> 10 mL?
Paha777 [63]

Answer:

That unknown substance is water

Explanation:

3 0
3 years ago
The heat of vaporization for benzaldehyde is 48.8 kj/mol, and its normal boiling point is 451.0 k. use this information to deter
user100 [1]

Answer:

The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

Explanation:

  • To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
  • The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
  • The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
  • ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
  • Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
  • ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
  • ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
  • (760 torr /P₂) = 0.01075
  • Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.

So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.

7 0
3 years ago
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