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2 years ago

Which phrase describes a feature of groundwater?

Chemistry

2 answers:

SashulF [63]2 years ago

7 0

Answer:

number 1

Explanation:

Groundwater mainly contributes the water into the surface water like streams, rivers, and lakes.

Hatshy [7]2 years ago

5 0

The first one is the correct one

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Did I get these correctly?

Luda [366]

Those are both correct! great job, keep up the good work (-:

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3 years ago

Calculate the number of joules needed to change the temperature of 40.0 g of water from 33.0 degree c to 43.0 degree c

nikdorinn [45]

Answer:

Explanation:

7 0

2 years ago

Explain the chemistry behind global warming in 3-5 sentences

Oliga [24]

Answer:

When factories mass produce something it produces smoke. That smoke can be harmful to something called the ozone layer. The ozone layer is part of earth's atmosphere that protects us from the suns burning heat. When that layer is damaged the sun's heat burns through heating up the world and melting ice causing the water levels to rise. All of this can make working conditions less safe, cause more flooding, and have the sun cause cancer.

8 0

2 years ago

What effect would you expect this to have on CO2 levels in the atmosphere?

VLD [36.1K]

expect what to have?!?!?!?

5 0

2 years ago

The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa

Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of $MgCl_2$ (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of $MgCl_2$ (solute) = 3.37 g

First we have to calculate the mass of solute.

$\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2$

$\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g$

Now we have to calculate the mass of solution.

$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g$

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg$

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

$\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%$

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

$\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%$

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0

3 years ago