MM = dRt/P
MM = (1.43 g/L )(0.0821 L * atm /Kmol)(273.15 K)/(1 atm)
MM = 32.1
The gas must have a molar mass of 32.1 which is very similar to that of Oxygen (32 g/mol).
Answer:
1.54 ml
2. 54 g
3. -43.7 °C
4. 97 g
5. 17.74 kJ
Explanation:
1. Volume of water that only came from the melted ice is;
Volume of water plus melted ice-volume of warm water
151 ml - 97 ml = 54 ml
2.Mass of water that came from the melted ice.
Mass=density of water * volume of water from melted ice
M=1 g/ml * 54 ml = 54 g
3. The change in temperature of warm water will be;
Lowest temperature of ice-water mixture-Temperature of warm water
ΔT=0.9-44.6 = -43.7
4. Mass of warm water will be;
Mass of warm water= density of water*volume of warm water
M=1g/ml * 97 = 97 g =0.097 kg
5.
Energy released by warm water as it cools
Q=mcΔT
Given , mass of warm water=m=97
c=4.184 j/g*°C = 4184 J/(kg.C)
Δ= - 43.7
Q=0.097*4184*43.7 =17735.56 J
17735.56/1000 =17.74 kJ
Two properties of gasses are that the have no defined shape or volume.
good luck my man
Answer:
When an archer pulls back the bowstring, some amount of elastic potential energy is gained by the flexible limbs of the bow. The more an archer pulls back, the more potential energy will be gained by the limbs of the bow due to stretching. When the bowstring is released, the arrow moves forward very quickly. What happens here is that the potential energy that is gained by the bow due to stretching is being quickly transferred to the arrow in the form of kinetic energy, and so, it moves forward.