Answer:
Below in bold.
Step-by-step explanation:
Using the point-slope form of a straight line equation:
y - y1 = m(x - x1)
y - (-1)) = -2/5(x - -10)
y + 1 = -2/5(x + 10)
y + 1 = -2/5x - 4
y = -2/5x - 5.
In standard form this is:
2x + 5y = -25.
Answer:
The given equation is NOT justified.
Step-by-step explanation:
Here, the given equation is
= 
Now, here Consider the left hand side and simplifying the left side by operating on the like terms,
⇒
= 
=
Here, Left side of equation ≠ Right side of the equation
Hence,
≠ 
The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
A is true, b is true, but c d aren’t and e is