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3 years ago

Describe the location of point (4,2) on a coordinate plane. Enter a number in each box to complete the sentence.

Mathematics

1 answer:

vovikov84 [41]3 years ago

3 0

Answer:

2 units up and 4 units to the right.

Step-by-step explanation:

It is 2 units up and 4 units to the right because since the x-coordinate is positive, that means the point is to the right of the origin and since the y-coordinate is positive, that means the point is above the origin.

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. When the last 3 digits of a year (such as

Nataliya [291]

Answer:

A ; 23rd century

Step-by-step explanation:

Here, we want to select which of the options is next to have a descending year.

Since all are in the same century i.e 20-something, we do not have an issue with the first digit.

What we need to work on is the last three digits;

We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.

The most recent of all these is the year 2210, so what century does this belong?

Kindly note that, the years 2001-2100 belong to the 21st century.

The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century

The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century

8 0

3 years ago

PLEASE HELP!!!<br> ANSWER ALL 4

wlad13 [49]

Answer:

1 and 8 are alternate exterior

8 and 5 are corresponding

3 and 2 are vertical

6 and 3 are alternate interior

4 0

2 years ago

Read 2 more answers

se an inequality symbol (<, >, =, ≠) to compare 5 + (−4) _____ 14 + (−13) A. > B. = C. ≠ D.

qwelly [4]

5+(-4)= 1
14+(-13)= 1
So the answer is B. =
I hope this helps

3 0

3 years ago

Read 2 more answers

What is the d stand for????

SOVA2 [1]

Answer:

The missing variable

Step-by-step explanation:

D=2

5 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago