All categories

3 years ago

Explain why a parachute would be useless if you went to the Moon?

Physics

2 answers:

NikAS [45]3 years ago

8 0

Gravity would be extremely weak, not to mention there’s no air to catch the chute

andrezito [222]3 years ago

7 0

Because you would fall so slow that you would not need one.

You might be interested in

60 POINTS SO PLEASE HELP ME To add vectors in a straight line ______________ and ______________ are considered positive directio

tankabanditka [31]

Answer:

The answer to your question is

Explanation:

To add vectors in a straight line _right_________ and ___upwards_______ are considered positive directions. __left________ and __downwards____________ are considered negative directions.

I hope it helps you

7 0

3 years ago

A uniform solid ball has a mass of 20 g and a radius of 5 cm. It rests on a horizontal surface. A sharp force is applied to the

Lapatulllka [165]

Answer:

i think the answer is 32 something

Explanation:

4 0

3 years ago

Pani-rosa [81]

The total displacement is 4.0 m east.

4 0

3 years ago

Millikan is doing his oil drop experiment. He has a droplet with radius 1.6 µm suspended motionless in a uniform electric field

swat32

Answer:

The charge on the droplet is $3.106\times10^{-16}\ C$ .

Yes, quantization of charge is obeyed within experimental error.

Explanation:

Given that,

Radius = 1.6μm

Electric field = 46 N/C

Density of oil = 0.085 g/cm³

We need to calculate the charge on the droplet

Using formula of force

$F= qE$

$mg=qE$

$V\times\rho\times g=qE$

$q=\dfrac{V\times\rho}{E}$

$q=\dfrac{\dfrac{4}{3}\pi\times r^3\times\rho\times g}{E}$

Put the value into the formula

$q=\dfrac{\dfrac{4}{3}\times\pi\times(1.6\times10^{-6})^3\times85\times9.8}{46}$

$q=3.106\times10^{-16}\ C$

We need to calculate the quantization of charge

Using formula of quantization

$n = \dfrac{q}{e}$

Put the value into the formula

$n=\dfrac{3.106\times10^{-16}}{1.6\times10^{-19}}$

$n=1941.25$

Yes, quantization of charge is obeyed within experimental error.

Hence, The charge on the droplet is $3.106\times10^{-16}\ C$ .

Yes, quantization of charge is obeyed within experimental error.

7 0

3 years ago

Read 2 more answers

Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they

maw [93]

This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is:

Ff = UsN

where Us is the coefficient of static friction and N is the normal force.

In order to get the crate moving you must first apply enough force to overcome the static friction:

Fapplied = Ff

Since Fapplied = 43 Newtons:

Fapplied = Ff = 43 = UsN

and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11

43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2

7 0

3 years ago

Read 2 more answers