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stepan [7]
4 years ago
6

I’m driving down the highway at 75.0 miles/hour, how fast is that in m/seconds?

Chemistry
1 answer:
Aliun [14]4 years ago
4 0

Answer:

1.25 miles/ 1 minute

60x1.25=7.50

Explanation:

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What is the formula for the compound copper (II) sulfate pentahydrateA. C2S3•6H2O
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Answer:

D

copper (II) sulfate pentahydrate

==>

CuSO _{4}.5H _{2}O

8 0
3 years ago
Lens coating are made of A.teflon B.bakelite C.melamine D.PVC
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C. melamine

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a thin coating that eliminates reflections and glare from the front and back surfaces of your lenses.

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3 years ago
The term that describes two or more objects in a system reaching the same temperature is
Galina-37 [17]

The correct answer is Thermal Equilibrium

Explanation:

The term "thermal equilibrium" is used when two or more objects have the same temperature and therefore there is not an exchange of heat between them. This occurs when the objects had a different temperature at the beginning but due to a close contact heat is transferred from one object to the other until an equilibrium or same temperature is reached. For example, a hot cup over a table or any other surface will transfer the heat to the surface, but after some time both the cup and the surface will have the same temperature or will reach thermal equilibrium.

7 0
4 years ago
How many moles in 2.33E25 molecules of NO?
Sindrei [870]

Answer:

0.0258 mol <em>Answer</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
goldfiish [28.3K]
The balanced chemical reaction:

<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

<span>0.06 mol Cu ( 63.55 g Cu / 1 mol Cu ) = 3.81 g Cu excess</span>
3 0
3 years ago
Read 2 more answers
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