Answer:
pH = 10.38
Explanation:
∴ molar mass C9H13N = 135.21 g/mol
∴ pKb = - log Kb = 4.2
⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]
∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M
mass balance:
⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)
charge balance:
⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water
⇒ [C9H20O3N+] = [OH-].......(2)
(2) in (1):
⇒ [C9H13N] = 1.516 E-3 - [OH-]
replacing in Kb:
⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])
⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0
⇒ [OH-] = 2.3985 E-4 M
∴ pOH = - Log [OH-]
⇒ pOH = 3.62
⇒ pH = 14 - pOH = 14 - 3.62 = 10.38
Answer:
ΔH = 41.7 kj
Given data:
Mass of ethanol = 50 g
Heat required to vaporize = ?
Boiling point of ethanol = 78.3°C
Molar heat of vaporization = 38.6 kj/mol
Solution:
First of all we will calculate the number of moles.
Number of moles = mass / molar mass
Number of moles = 50 g/ 46.07 g/mol
Number of moles = 1.08 mol
ΔH = 38.6 kj/mol ×1.08 mol
ΔH = 41.7 kj
Explanation:
Answer:
Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.
Data:
Calculations:
Don’t Put this as your answer
Answer:
Moles to grams carbon dioxide
1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.
Explanation:
Moles to grams carbon dioxide
1 mole is equal to 1 moles Carbon Dioxide, or 44.0095 grams.
