Answer:
e_12=1-Tc/Th
This is same as the original Carnot engine.
Explanation:
For original Carnot engine, its efficiency is given by
e = 1-Tc/Th
For the composite engine, its efficiency is given by
e_12=(W_1+W_2)/Q_H1
where Q_H1 is the heat input to the first engine, W_1 s the work done by the first engine and W_2 is the work done by the second engine.
But the work done can be written as
W= Q_H + Q_C with Q_H as the heat input and Q_C as the heat emitted to the cold reservoir. So.
e_12=(Q_H1+Q_C1+Q_H2+Q_C2)/Q_H1
But Q_H2 = -Q_C1 so the second and third terms in the numerator cancel
each other.
e_12=1+Q_C2/Q_H1
but, Q_C2/Q_H2= -T_C/T'
⇒ Q_C2 = -Q_H2(T_C/T')
= Q_C1(T_C/T')
(T1 is the intermediate temperature)
But, Q_C1 = -Q_H1(T'/T_H)
so, Q_C2 = -Q_H1(T'/T_H)(T_C/T') = Q_H1(T_C/T_H) So the efficiency of the composite engine is given by
e_12=1-Tc/Th
This is same as the original Carnot engine.
Given:
The speed of sound is 340 m/s
Time for the echo is 5.2 s.
Let h = the depth of the canyon.
Because the sound of your voice travels to the bottom of the canyon and back to your ear, the total distance traveled is 2h.
By definition,
distance = velocity * time.
Therefore
2h = (340 m/s)*(5.2 s) = 1768 m
h = 884 m
Answer: The depth is 884 m.
Answer:
option (D)
Explanation:
If we plot a graph between the velocity of the object and the time taken, the slope of graph gives the value of acceleration of the object and the area under the graph gives the product of velocity and time taken that means it is displacement
1) Current
2) Atoms
3) Wire
4) Negative
5) Neutron
6) Shock
7) Switch
8) Static
9) Volt
10) Battery
11) Dam
12) Thomas Edison
13) Benjamin Franklin
14) Alessandro Volta
15) Michael Faraday
I would say that these would be your correct answers, btw I'm doing something that is close to the same right now
Hope this helps :)
Answer:
The speed of the apple will be 2.81 m/s when the arrow enters it.
Explanation:
We can find the speed of the apple by conservation of linear momentum:
Where:
is the mass of the apple = 100 g = 0.1 kg
is the mass of the arrow = 2.5 g = 0.0025 kg
and 
is the initial and final speed of the apple respectively
and 
is the initial and final speed of the arrow respectively
Since the apple was originally at rest ( = 0) and knowing that = when the arrow enters into the apple, we have:
Therefore, the speed of the apple will be 2.81 m/s when the arrow enters it.
I hope it helps you!
