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snow_lady [41]
3 years ago
11

xFormula1" title="\color {pink}\boxed{\colorbox{black} { QUESTION♡}}" alt="\color {pink}\boxed{\colorbox{black} { QUESTION♡}}" align="absmiddle" class="latex-formula">
Find three consecutive odd integers for which the sum of the first and the second is equal to nine more than the third.​
Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0

The three consecutive odd numbers are 11, 13, and 15.

<h3 />

<h3>Odd numbers:</h3>

Odd numbers are numbers when divided by 2 produces a remainder. This numbers cannot be divided exactly into pairs. example are 3, 5, 7, 9, 11 etc.

The odd integers are consecutive. Therefore, the odd numbers can be represented as follows:

  • x
  • x + 2
  • x + 4

The sum of the first and the second is equal to nine more than the third.​ Therefore,

  • x + x + 2 = 9 + x + 4

2x + 2 = x + 13

2x - x = 13 - 2

x = 11

Therefore, the consecutive odd numbers are as follows:

  • 11, 13, 15

learn more on odd numbers: brainly.com/question/123862?referrer=searchResults

Goryan [66]3 years ago
4 0

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He doesn't get the price of talent

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