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MissTica
3 years ago
8

Function 1 is defined by the equations r=3/4t +5 Function 2 is defined by the following table

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Function 2 has a greater y-intercept

<h3>Graphs</h3>

Graphs can be used to represent functions, equations, tables and relations

<h3>Equations</h3>

The equation of function 1 is given as:

r =\frac 34t + 5

To calculate the y-intercept, we set t to 0.

So, we have:

r =\frac 34 \times 0 + 5

r =5

For the table of function 2, the y-intercept is 5.25

By comparison:

5.25 is greater than 5

Hence, function 2 has a greater y-intercept

Read more about graphs and functions at:

brainly.com/question/3939432

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Answer:

the lines are neither perpendicular or parallel

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3 years ago
What are scale drawings? can you give an example?
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Hope this helps :) 
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The length of a rectangle is 14 inches and it’s area is (42x+56) square inches. Factor the expression for the area. Write an exp
sergey [27]

Answer:

Step-by-step explanation:

Area = 42x + 56

length * width = 14* 3x + 14*4

14 * width = 14*(3x+4)

width=\frac{14*(3x+4)}{14}\\\\width=3x+4

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How many 2/3 cups servings are in a 4 cup container of food
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6 0
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Read 2 more answers
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
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