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Anarel [89]
3 years ago
5

Baseball outfielder throws a baseball of mass 0.15 kg at a speed of 40 m/s and initial angle of 30. What

Physics
1 answer:
Archy [21]3 years ago
3 0

Explanation:

At the top of the the ball's trajectory, there is only the horizontal component of the initial velocity, which is v_0\cos30, so the kinetic energy of the ball at this point is

KE = \frac{1}{2}m(v_0\cos30)^2

\;\;\;\;\;= \frac{1}{2}(0.15\:\text{kg})[(40\:\text{m/s})\cos30]^2

\;\;\;\;\;= 90\:\text{J}

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