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seropon [69]
3 years ago
10

Quick! how did Daniel hale Williams contribute to science?

Physics
1 answer:
My name is Ann [436]3 years ago
3 0
He preformed the first ever successful open heart surgery
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What type of subsurface material is able to store groundwater?
notka56 [123]
<span>Porous material has many spaces that can hold(store) groundwater.</span>
4 0
3 years ago
Need a little help here :(
Goshia [24]

Answer:

The output out be 200

Explanation:

Hope this helps :))

8 0
3 years ago
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Which has the most momentum?
boyakko [2]

Answer:

Both objects have the same magnitude of momentum.

Explanation:

If an object of mass m is moving at a velocity of v, the momentum of that object would be m\, v.

The 100\; {\rm g} (0.1\; {\rm kg}) object is moving at a speed of 1\; {\rm m\cdot s^{-1}}. The magnitude of the momentum of this object would be 0.1\; {\rm kg} \times 1\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Similarly, the momentum of the 1\; {\rm g} (10^{-3}\; {\rm kg}) object moving at a speed of 100\; {\rm m\cdot s^{-1}} would be 10^{-3}\; {\rm kg} \times 100\; {\rm m\cdot s^{-1}} = 0.1\; {\rm kg \cdot m \cdot s^{-1}}.

Hence, the magnitude of momentum is the same for the two objects.

7 0
2 years ago
Why do the magnetic forces acting on the coil change as the current running through the coil changes?
VladimirAG [237]

Answer: The changing magnetic field caused by the material's motion induces a current in the coil of wire proportional to the change in field. If a 0 is represented, the magnetic field does not change between the two domains of a bit, so no current is induced as the magnetic material passes the coil.

4 0
3 years ago
what is the electric potential at point A in the electric field created by a point charge of 5.5 • 10^-12 C? estimate k as 9.00
Hitman42 [59]

The electric potential at point A in the electric field= 0.099 x 10 ⁻¹v

<u>Explanation</u>:

Given data,

charge = 5.5 x 10¹² C

k =9.00 x 10⁹

The electric potential V of a point charge can found by,

V= kQ / r

Assuming, r=5.00×10⁻² m

V= 5.5 x 10⁻¹²C x  9.00 x 10⁹ / 5.00×10⁻² m

V=  49.5 x 10⁻³/ 5.00×10⁻²

Electric potential V=  0.099 x 10⁻¹v

3 0
3 years ago
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