Answer fast but correctly
2 answers:
You might be interested in
Answer:
BM: <u>y = (2/3) x + 16/3</u> with segment length of 2.77
Step-by-step explanation:
AC formula: m = (6-0)/(0-4) = -3/2
(y-0)/(x-4) = -3/2 y = (-3/2)x + 6 ... (1)
BM slope: BM⊥ AC m = 2/3
BM formula: (y-4) / (x- -2) = (y-4) / (x+2) = 2/3
y-4 = 2/3 x + 4/3
<u>y = (2/3) x + 16/3</u> ... (2) -2≤x≤0.31
intercept of AC and BM (M) from (1) and (2): (-3/2)x + 6 = (2/3) x + 16/3
(13/6) x = 2/3 x = (2/3) / (13/6) = 4/13 ≈ 0.31
y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54
M (4/13 , 72/13) or (0.31 , 5.54)
segment BM = √(4/13 - -2)² + (72/13 - 4)² = √1300/169 = 2.77
Answer/Step-by-step explanation:
Total Distance = 3Ft
a) Determine the amplitude and period of a sinusoidal function that models the bobbing buoy.
Amplitude = 3/2 = 1.5 period = 10 second
No ph. Shift
b) Write an equation of a function that models the buoy with x=0 at its highest point.
y= 1.5 cos ( )