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joja [24]
2 years ago
10

Answer fast but correctly​

Mathematics
2 answers:
Alenkinab [10]2 years ago
8 0

Answer:

The answer is A

3^2=9

9-2=7

Answer 7

olasank [31]2 years ago
3 0

{m}^{2}  - n \\ Given, \:  \: m = 3 \:  \: n = 2, then, \\ \:  \:  {(3)}^{2}  - 2 \\  = 9 - 2 \\  = 7

<u>Answer</u><u>:</u>

<u>a.</u><u> </u><u>7</u>

Hope you could understand.

If you have any query, feel free to ask.

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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
Felipe, Pedro y Miguel son fanáticos del cine. Felipe asiste cada 3 días; Pedro cada 6 días y Miguel cada 5 días. Los tres van j
lilavasa [31]

Answer:

Opción C, 30 días.

Step-by-step explanation:

Sabemos que:

Felipe asiste al cine cada 3 días

Miguel asiste cada 5 días.

Pedro asiste cada 6 días.

Los tres van juntos un día,  ¿dentro de cuántos días irán otra vez juntos?

Los 3 volverán a ir juntos luego de N días, tal que N es el menor múltiplo común de 3, 5 y 6.

Como 6 es múltiplo de 3, podemos ignorar al 3, y solo considerar al menor múltiplo en común de 5 y 6.

Además, como podemos reescribir estos números como un producto de números primos, así obtenemos:

6 = 2*3

5 = 5*1

Estos números no comparten factores entre ellos, por lo que el menor múltiplo entre 5 y 6 es simplemente 5*6 = 30

Entonces podemos concluir que N = 30

Felipe, Pedro y Miguel irán juntos al cine nuevamente dentro de 30 días.

La opción correcta es C.

5 0
3 years ago
A rectangle has a perimeter of 71.8 yards and a height of 3.3 yards. What is the length of the base?
Studentka2010 [4]

The length of the base is 32.6

3.3 + 3.3 = 6.6

Subtract 6.6 from 71.8 : 65.2

Divide that by 2 : 32.6

7 0
3 years ago
Read 2 more answers
Graph the line y=−3x+b if it is known that the graph goes through point:<br> b<br> B(5, 2)
egoroff_w [7]

Answer: y=-3x+17

b = 17

4 0
3 years ago
Write the fraction as an equivalent fraction with the given denominator 7/4 = _/20
zzz [600]

Answer:

35/20

Step-by-step explanation:

20 divided by 4 = 5

so our multiple is 5

5 x 4 = 20

so we have to do the same to the numerator

5 x 7 = 35

Simplified= 1 3/5

4 0
2 years ago
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