The question is incomplete, here is the complete question:
Calculate the pH at of a 0.10 M solution of anilinium chloride 
. Note that aniline 
is a weak base with a 
of 4.87. Round your answer to 1 decimal place.
<u>Answer:</u> The pH of the solution is 5.1
<u>Explanation:</u>
Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).
To calculate the pH of the solution, we use the equation:
![pH=7-\frac{1}{2}[pK_b+\log C]](https://tex.z-dn.net/?f=pH%3D7-%5Cfrac%7B1%7D%7B2%7D%5BpK_b%2B%5Clog%20C%5D)
where,
= negative logarithm of weak base which is aniline = 4.87
C = concentration of the salt = 0.10 M
Putting values in above equation, we get:
![pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1](https://tex.z-dn.net/?f=pH%3D7-%5Cfrac%7B1%7D%7B2%7D%5B4.87%2B%5Clog%20%280.10%29%5D%5C%5C%5C%5CpH%3D5.06%3D5.1)
Hence, the pH of the solution is 5.1
(B) Copper (II) sulfite has the chemical formula CuSO3.
Copper(II) sulfate is the chemical compound CuSO4, although it is also known as blue vitriol, Roman vitriol, the vitriol of copper, and bluestone. Copper sulfate is most frequently found as its pentahydrate, which has the chemical formula CuSO4. 5H2O.
For further information on the chemical name of the compound cu2co3, see its chemical formula. This compound is made up of copper cations (Cu2 ) and carbonate anions (CO3), and as a result is known as copper carbonate and is categorized as a salt.
CuCO is the chemical formula for copper(II) carbonate, also known as cupric carbonate. It is an ionic solid (a salt) that, at room temperature, consists of
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