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wolverine [178]
3 years ago
6

Can you help me with these questions?

Chemistry
1 answer:
ZanzabumX [31]3 years ago
7 0
1.) C. Microwave, visible, gamma
4.) B. I’m pretty sure frequency increases from left to right and wavelength gets shorter

1.) A. Atomic bomb
2.) C. GPS
3.) A. FM radio
4.) B. Radar detector

It’s been like 2-3 years since I’ve done this stuff so I’m not entirely sure‍♀️
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Select the phrase that completes each statement.
Karolina [17]

Answer:

Honey is A MIXTURE AND A SOLUTION

Grape juice is A MIXTURE AND A SOLUTION

Sand on the beach is A MIXTURE BUT NOT A SOLUTION

A mixture of carbon dioxide and nitrogen gases is A MIXTURE AND A SOLUTION

Rubbing Alcohol is A MIXTURE AND A SOLUTION

Explanation:

For edg 2020

3 0
4 years ago
MARK AS BRAINLIEST ASAP plz thanks
dimulka [17.4K]
The answer is C. If u have any other questions don’t be afraid to ask.
3 0
3 years ago
Read 2 more answers
What is the difference between atomic mass and number?
OlgaM077 [116]
Atomic mass is the number of protons and neutrons in an element while an atomic number is the number of protons in the element.
5 0
3 years ago
Explain the process of photosynthesis. Make sure to give the inputs and outputs.
olga55 [171]

Answer:

Photosynthesis is the process by which carbon dioxide and water are converted into oxygen and glucose. The plant consumes glucose as food, and oxygen is produced as a by-product. During cellular respiration, oxygen and glucose are converted to water and carbon dioxide. Water and carbon dioxide are by-products of the process, while ATP is the energy that is transformed. Water, carbon dioxide, and energy in the form of sunshine are all inputs in photosynthesis, and the outputs are glucose and oxygen.

4 0
3 years ago
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A cylindrical specimen of some metal alloy having an elastic modulus of 129 GPa and an original cross-sectional diameter of 4.4
miss Akunina [59]

Explanation:

The cross-sectional area of the specimen is calculated as follows.

         A_{o} = \frac{pi}{4} d^{2}

                     = \frac{3.14}{4} \times (\frac{4.4}{1000})^{2}

                     = 1.5197 \times 10^{-5} m^{2}

Equation of stress is as follows.

              \sigma = \frac{F}{A_{o}}

And, the equation of strain is as follows.

             \epsilon = \frac{\Delta l}{l_{o}}

Hence, the Hook's law is as follows.

              E = \frac{\sigma}{\epsilon}

       E = \frac{\frac{F}{A_{o}}}{\frac{\Delta l}{l_{o}}}

          = \frac{F \times l_{o}}{A_{o} \times \Delta l}

or,    l_{o} = \frac{E \times \Delta l \times A_{o}}{F}          

                   = \frac{129 \times 10^{9} \times \frac{0.48}{1000} \times 1.662 \times 10^{-5}}{1570}

                  = 0.6554 m

or,         l_{o} = 655.4 mm

Thus, we can conclude that the maximum length of the specimen before deformation if the maximum allowable elongation is 0.48 mm is 655.4 mm.

5 0
4 years ago
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