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34kurt
2 years ago
8

Question 2

Mathematics
1 answer:
kirill115 [55]2 years ago
5 0

Step-by-step explanation:

the first is

2(x - 1/2)² = 2(x² - 2×1/2×x + 1/4) = 2x² - 2x + 1/2

so, no, this is not the same.

the second is

2(x - 1/4)² = 2(x² - 2×1/4×x + 1/16) = 2x² - x + 1/8

that is the correct answer.

the third is

2(x - 1/8)² = 2(x² - 2×1/8×x + 1/64) = 2x² - 1/2 x + 1/32

so, no, this is not the same.

the fourth is

2(x - 1/16)² = 2(x² - 2×1/16×x + 1/256) = 2x² - 1/4 x + 1/128

so, no, this is not the same.

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How are the graphs of the functions f(x) = . 16and g(x) = 3/64 related?
Natalija [7]

Answer: A  there are equivalent.

Step-by-step explanation:

f(x) = \sqrt{16}^x  reduces to  f(x)=4^{x}  

g(x)= \sqrt[3]{64}^{x}   also reduces to g(x) = 4^{x}  

8 0
3 years ago
Xavier is buying notebooks for school. The table below shows the number of notebooks he can buy and the total cost.
DochEvi [55]

Answer:

2.41 * n = y

Step-by-step explanation:

From the table, we can notice that the value;

y/n is a constant for each of the rows

this represents the individual costs of each of the books

So, we have it that;

7.23/3 = 4.82/2 = 9.64/4 = $2.41

So, the books have a unit cost of $2.41

Hence, by multiplying the number of books n by 2.41 we can get the cost y

So mathematically, we have the relation as;

2.41 * n = y

7 0
3 years ago
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I really need to know the answer this fast please!!!!!!
Zepler [3.9K]
The answer is A I think
3 0
3 years ago
What is the slope on the graph?
Irina-Kira [14]

Answer:

-1/5

Step-by-step explanation:

5 0
3 years ago
I need answer ASAP<br> If f(x) = 2x+1 and g(x) = 3x-2 Find f[g(1)] =
Nadya [2.5K]

Answer:

f[g(1)] = 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 1

g(x) = 3x - 2

<u>Step 2: Find g(1)</u>

  1. Substitute in <em>x</em>:                    g(1) = 3(1) - 2
  2. Multiply:                               g(1) = 3 - 2
  3. Subtract:                              g(1) = 1

<u>Step 3: Find f[g(1)]</u>

  1. Substitute in g(1):                    f[g(1)] = 2(1) + 1
  2. Multiply:                                   f[g(1)] = 2 + 1
  3. Add:                                         f[g(1)] = 3
7 0
3 years ago
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