Answer:
It is 5.5 miles/hour if you are trying to figure out how fast john runs.
Step-by-step explanation:
if john run 2 mile/hour faster than lucy, you just have to add how fast lucy is running by 2. This will equal john's miles/hour. now you times 5.5 by how many hours he runs.
Answer:
(x - 3)^2 + (y + 2)^2 = 2^2.
According to the given statement, we can get the equation:
50 - 3x = 1/2 (50-x)
where x = amount removed from bag two, 3x removed from bag one
Then we multiply both sides by 2 (to eliminate the ½)
100-6x= 50-x
Add 6x to both sides
100= 50-5x
Then subtract 50 from both sides
50=5x
Lastly, divide by 5
10=x
Therefore 10 kg of sugar was removed from bag 2
further, 3x= 30, so 30 kg of sugar was removed from bag 1.
50-30=20 kg remaining in bag 1.
<span>50-10=40 kg remaining in bag 2.</span>
Jack has 212 marbles.
Step-by-step explanation:
Jack and Watson have = 365 marbles
Jack and Asher have = 263 marbles
Let,
x be the marbles Jack have
y be the marbles Watson have
z be the marbles Asher have
According to given statement;
x+y=365 Eqn 1
x+z=263 Eqn 2
Watson has three times as many marbles is Asher.
y=3z Eqn 3
Putting y=3z in Eqn 1;
x+3z=365 Eqn 4
Subtracting Eqn 2 from Eqn 4
![(x+3z)-(x+z)=365-263\\x+3z-x-z=102\\2z=102](https://tex.z-dn.net/?f=%28x%2B3z%29-%28x%2Bz%29%3D365-263%5C%5Cx%2B3z-x-z%3D102%5C%5C2z%3D102)
Dividing both sides by 2
![\frac{2z}{2}=\frac{102}{2}\\z=51](https://tex.z-dn.net/?f=%5Cfrac%7B2z%7D%7B2%7D%3D%5Cfrac%7B102%7D%7B2%7D%5C%5Cz%3D51)
Putting z=51 in Eqn 2
![x+51=263\\x=263-15\\x=212](https://tex.z-dn.net/?f=x%2B51%3D263%5C%5Cx%3D263-15%5C%5Cx%3D212)
Jack has 212 marbles.
Keywords: linear equations, subtraction
Learn more about linear equations at:
#LearnwithBrainly
One: Graphs help you solve equations, and equations help you solve graphs.
<span>Because the graph is a diagram of the equation, showing at its simplest the y answer for each value of x.
Two: </span>You have to solve for y, graph it, and then find where the lines intersect.You can take a table and put in all the x and y valuesThen graph it.. And see where it intersectsBecause usually these equations are lines.<span>
</span>