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riadik2000 [5.3K]
3 years ago
8

!!30 POINTS!!

Mathematics
1 answer:
lana66690 [7]3 years ago
8 0
For this case we have the following functions:
 f (x) = 3x + 4
 g (x) = 2 ^ x - 1
 The intersection with the y axis of the original functions is:
 f (0) = 3 (0) + 4 = 0 + 4 = 4
 g (0) = 2 ^ 0 - 1 = 1 - 1 = 0
 The transformations that must be applied so that they have the same intersection with the y axis are:
 f (x) - 3
 g (x) + 1
 Answer:
 
f (x) - 3
 
g (x) + 1
 
option 1
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4 ( x - 2) > 5

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About 1.15 million people live in a circular region with a population density of about 18,075 people per square kilometer. Find
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zoey made 6 3/4 cups of fruit salad for a picnic they ate 1/3 of the fruit salad for a picnic they ate 1/3 of the fruit salad Ho
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3 years ago
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
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