The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
He starts on the 1st floor. He then goes up 18 floors:
1 + 18 = 19
He took the stairwell down 3 floors
19 - 3 = 16
He then takes the elevator down 8 floors
16 - 8 = 8
He then takes the stairwell up 5 floors for his afternoon meeting
8 + 5 = 13
C. thirteenth is your answer
hope this helps
Answer:
B. (8,4)
Step-by-step explanation:
To find the solution of the system, look at where the lines intersect. The intersecting point is (8,4). The solution to the system of equations is (8,4).
We presume you want to find the number.
Let n represent the number.
6 + n/4 = 3 . . . . . . . 6 more than the quotient of a number and 4 is 3.
To solve this, we "undo" what is done to the number. First we undo the addition of 6 by adding its opposite, -6. We add -6 to both sides of the equation so the equal sign remains valid.
6 -6 +n/4 = 3 -6
n/4 = -3 . . . . . . . . simplify
Now, we need to undo the division by 4. We do that by multiplying by 4. Again, we must do that to both sides of the equation so the equal sign remains valid.
4(n/4) = 4(-3)
n(4/4) = -12
n = -12
The number is -12.
Answer: We are given:
During the first 10 days, the stock increases by $0.30 per day.
During the next 10 days, the stock decreases by $0.45 per day.
During the last 10 days, the stock increases by $0.25 per day.
We have to find total amount the stock increase over the first 10 days.
The total amount the stock increase over the first 10 days is:
Therefore, during the first 10 days the stock was increased by $3.
