Question

An hibernating bear accumulates 25 kg of a triglyceride (846 g/mol) comprising the following fatty acids: C16, C17 and C18∆9. How many grams of β-hydroxybutyrate (104 g/mol) can the bear produce from this triglyceride during its hibernation?

Answer 1

The quantity of β-hydroxybutyrate the bear can produce

during hibernation is 3,073.30grams.

Hibernation is defined as the period of less activity by animals to conserve energy to survive coarse weather conditions.

A typical example of an animal that hibernates is the bear.

From the question, a bear is able to accumulate 25kg (25000grams) of triglyceride.

To calculate quantity of β-hydroxybutyrate that would be produced from 25kg triglyceride;

846g of triglyceride = 104grams of β-hydroxybutyrate

25000g of triglyceride = x grams

(Cross multiple to solve for x grams)

X = 104 × 25000/846

$x = \frac{104 \times 25000}{846}$

$x = \frac{2600000}{846}$

$x = 3073.30grams$

Therefore, the quantity of β-hydroxybutyrate the bear can produce during hibernation is 3,073.30grams.

Learn more about hibernation here:

brainly.com/question/3047864