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Dahasolnce [82]
3 years ago
13

Annie comes to a sudden stop to avoid hitting a deer crossing the road at night. As she hits the breaks, her speed drops from 12

m/s to zero in 1.5 seconds.(p1) How far did she travel during that time? (p2)What was her average acceleration?
Distance(p1)
9 m
8 m
10 m
13.5 m

Acceleration(p2)
6 m/s2
8 m/s2
12 m/s2
16 m/s2
Physics
1 answer:
Anon25 [30]3 years ago
7 0

Answer:

1. around 22m

Explanation:

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Which factor listed below most likely results in the loss of genetic variation from small populations?
Snezhnost [94]

The correct choice is genetic drift.

genetic drift is known as the variation in alleles number within a population and it mainly happens in small population where chances of losing an alleles are larger. it is common effect observed when significant number in a population die or when there is significant reduction in birth. hence genetic drift results in loss of genetic variation

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In this experiment, you will use a track and a toy car to explore the concept of movement. You will measure the time it takes th
LenKa [72]
A question you can gather from this experiment is figuring out the distance traveled by the car, and how far it went. A simple solve of X equation could be used.
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4 years ago
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A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 met
andrew11 [14]

Answer: 3 m/s^2

Explanation:

The acceleration of the motorcycle is given by

a=\frac{v-u}{t}

where

v=24 m/s is the final velocity of the motorcycle

u=15 m/s is the initial velocity

t=3 s is the time taken

Substituting these numbers into the equation, we find

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4 years ago
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How many neutrons does element X have if it’s atomic number is 28 and it’s mass number is 81?
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Answer:

53

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4 years ago
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Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km  west

velocity V1 = 8.9 km/h

distance B = 4.5 km  east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7     ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x )  / 8.9      .............2

now equating equation 1 and 2

time A = time B

x / 7  =   ( 10.2 - x )  / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

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