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Nadya [2.5K]
3 years ago
7

The factors that affects the gravitational force between two objects are

Physics
1 answer:
viva [34]3 years ago
8 0

-- The product of their two masses (no matter what
the individual masses happen to be),

-- The distance between the centers of mass of the two masses.

Nothing else affects the force of gravity between two objects,
and nothing in between them can 'shield' or block it.


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In the equation for centripetal force, which expression represents the centripetal acceleration of the object? mv2 StartFraction
Sphinxa [80]

Answer: \frac{V^{2}}{r}

Explanation:

According to Newton's 2nd Law of motion the force F is proportional to the mass Fm and acceleration a:

F=m.a (1)

On the other hand, the equation for the Centripetal force is:

F=\frac{mV^{2}}{r} (2)

Where:

V is the velocity

r is the radius of the circular motion

Making (1) and (2) equal:

m.a=\frac{mV^{2}}{r} (3)

Hence:

a=\frac{V^{2}}{r} This is the expression for the centripetal acceleration

It should be noted, this acceleration is directed toward the center of the circumference of the circular motion (that's why it's called centripetal acceleration).

3 0
3 years ago
Read 2 more answers
What happens when light enters a pair of glasses
alexdok [17]

Answer:

It refracts when it hits the glass.

6 0
3 years ago
A car traveling with an initial velocity of 12 m/s accelerates at a constant rate of 2.2 m/s2 for a time of 4 seconds.
bazaltina [42]
So what's the question?
4 0
3 years ago
An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert
cupoosta [38]

Answer:

The compression in the spring is 5.88 meters.                

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, k=4.2\times 10^5\ N/m

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

mgh=\dfrac{1}{2}kx^2

x is the compression in spring

x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m

So, the compression in the spring is 5.88 meters.                                                                                                                  

6 0
3 years ago
The change in motion (acceleration) of an object depends on
7nadin3 [17]

Answer:

BOTH the size of the force AND the mass of the object

Explanation:

Acceleration of an object is the rate of change of its velocity.

The relation between force, mass and acceleration is given by the formula as follows :

F = ma

m is mass

a is acceleration

It would mean that the change in motion or the acceleration of an object depends on both the size of the force and the mass of the object. Hence, the correct option is (c).

8 0
3 years ago
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