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3 years ago

The factors that affects the gravitational force between two objects are

1 answer:

8 0

-- The product of their two masses (no matter what
the individual masses happen to be),

-- The distance between the centers of mass of the two masses.

Nothing else affects the force of gravity between two objects,
and nothing in between them can 'shield' or block it.

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Jonah observes the Sun through a special filtered telescope during a total solar eclipse. He sees a red ring and a faint white r

ivann1987 [24]

The answer would be C. chromosphere and corona.

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3 years ago

Read 2 more answers

You pick up a 3.4-kg can of paint from the ground and lift it to a height of 1.8 m. (a) how much work do you do on the can of pa

MariettaO [177]

(a) For the work-energy theorem, the work done to lift the can of paint is equal to the gravitational potential energy gained by it, therefore it is equal to

$W=mg\Delta h$

where m=3.4 kg is the mass of the can, g=9.81 m/s^2 is the gravitational acceleration and $\Delta h=1.8 m$ is the variation of height. Substituting the numbers into the formula, we find

$W=(3.4 kg)(9.81 m/s^2)(1.8 m)=60.0 J$

(b) In this case, the work done is zero. In fact, we know from its definition that the work done on an object is equal to the product between the force applied F and the displacement:

$W=Fd$

However, in this case there is no displacement, so d=0 and W=0, therefore the work done to hold the can stationary is zero.

(c) In this case, the work done is negative, because the work to lower the can back to the ground is done by the force of gravity, which pushes downward. Its value is given by the same formula used in part (a):

$W=mg \Delta h=(3.4 kg)(9.81 m/s^2)(-1.8 m)=-60.0 J$

8 0

4 years ago

when an incandescent light bulb is turned on, its thin wire filament heats up quickly. as the temperature of this wire filament

Leno4ka [110]

Well, we usually assume that the resistance of a circuit component
is constant and doesn't change. But the truth is that for anything
that conducts current, its resistance always increases somewhat
when it warms up.

For things like light bulbs, electric toasters, space heaters, electric
stove burners, the heat coils in a blow-dryer ... anything that's
designed to be really hot when it's doing its job ... the resistance
of those things increases significantly when they come up to their
operating temperatures.

6 0

3 years ago

The door handles are kept near the edges of door planks

Otrada [13]

Uh what’s the question

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3 years ago

What is the magnification of an astronomical telescope whose objective lens has a focal length of 74 cm and whose eyepiece has a

Novay_Z [31]

Answer:

The magnification of an astronomical telescope is -30.83.

Explanation:

The expression for the magnification of an astronomical telescope is as follows;

$M=-\frac{f_o}{f_e}$

Here, M is the magnification of an astronomical telescope, $f_e$ is the focal length of the eyepiece lens and $f_o$ is the focal length of the objective lens.

It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.

Put $f_o=74 cm$ and $f_e=2.4 cm$ in the above expression.

$M=-\frac{74}{2.4}$

M=-30.83

Therefore, the magnification of an astronomical telescope is -30.83.

5 0

3 years ago