The elements that form compounds difficulty in the fourth period in the periodic table
- In the fourth periodic table, there contain 18 elements that forms compounds difficulty beginning with potassium and ending with krypton – one element for each of the eighteen groups.
- This is as a result of the additional 10 electrons that are contributed by the the sublevel.
The period 4 transition metals are scandium (Sc), titanium (Ti), vanadium (V), chromium (Cr), manganese (Mn), iron (Fe), cobalt (Co), nickel (Ni), copper (Cu), and zinc (Zn).
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The balanced equation is as below
Na2CO3 +2 HCl → 2 NaCl +H2O + CO2
<u><em>Explanation</em></u>
step 1 : write the unbalanced chemical equation
that is Na2CO3 + HCl→ NaCl + H2O +CO2
Step 2: change the coefficient ( <em>number in front of chemical formula) </em>to make sure the number of atoms of an element are the same in both side.
By adding 2 in front of HCl and in front of NaCl balance the equation.
Therefore the balanced equation is as below
Na2CO3 +2HCl → 2NaCl +H2O +Co2
Answer:
The water molecule is comprised of two hydrogen (H) atoms and one oxygen atom, oxygen atom has 8 electrons, and each H has 1 electron. The H atoms bond to the oxygen by sharing a pair of electrons in what is called a covalent bond. In each pair of shared electrons, one electron is contributed by the H (black) and one from the oxygen (red).
Explanation:
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Answer:
The melting points of the second series of transition elements are electrons are entering to the type of orbital.
Explanation:
Transition elements have "d" band that can overlap with the "s' band to give a composite band. The composite band have six molecular orbitals per metal atom.
Half of the molecular orbitals are the anti bonding.So, maximum bonding occurs when the molecular orbitals contains six electrons i.e. the metal has six valence electrons per each metal atom.
When the maximum bonding occurs then it shows maximum melting point.
So, molybdenum shows melting point at and after that the electrons goes into the antibonding and reaches minimum for cadmium when the anti boning orbital is completely filled. So, the melting point of the cadmium is tex]321^{o}C[/tex].
Answer:
Number of moles of hydrogen are 0.022 mol.
Explanation:
Given data:
Volume of hydrogen = 546 mL
Temperature = 30°C
Pressure = 100.45 kpa
Number of moles of hydrogen = ?
Solution:
According to ideal gas equation,
PV = nRT
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
First of all we will convert the units,
Temperature = 30 + 273 = 303 K
Pressure = 100.45 /101 = 0.99 atm
Volume of hydrogen = 546 mL× 1L /1000 mL =0.546 L
Now we will put the values in formula,
PV = nRT
n = PV/RT
n = 0.99 atm × 0.546 L /0.0821 atm.L/mol.K × 303 K
n = 0.541 atm. L / 24.876 atm.L / mol
n = 0.022 mol