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2 years ago

6

The wholesale price for a desk is $102. A certain furniture store marks up the wholesale price by 25%. Find the price of the des

k in the furniture store.
PLZ HELP

1 answer:

denpristay [2]2 years ago

8 0

Answer:

I guess $197.06

Step-by-step explanation:

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Victor, Leo, and Kate together sold 87 tickets for the school banquet. Victor sold 32 tickets and Leo sold 26 tickets. How many

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The answer would be C. 29

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3 years ago

Which values of x would make a polynomial equal to zero if the factors of the

svp [43]

Answer:

x = 3 and x = 7

Step-by-step explanation:

Equate the product of the factors to zero, that is

(x - 3)(x - 7) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 7 = 0 ⇒ x = 7

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3 years ago

Please help me I don't know how to do these at all.

Arlecino [84]

Answer:

The quotient is (-x³ + 4x² + 4x - 8) and the remainder is 0

Step-by-step explanation:

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3 years ago

If 5 friends each had one part of a scarf that's 1 and 5/12 yards long what fraction of the scarf could each friend knit

zalisa [80]

Answer:

17/60 yards of scarf

Step-by-step explanation:

If 5 friends each had one part of a scarf that's 1 and 5/12 yards long what fraction of the scarf could each friend knit

To solve the above question:

5 friends = 1 5/12 yards

1 friend = x yards

Cross Multiply

5 × x = 1 × 1 5/12 yards

x = 17/12 yards ÷ 5

x = 17/12 yards × 1/5

x = 17/60 yards of scarf

6 0

3 years ago

During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

∴ The required probability = 0.5898

5 0

3 years ago