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lisov135 [29]
3 years ago
7

A light ray travels inside a horizontal plate of glass, striking its upper surface at an angle of incidence of 50°. This ray is

totally internally reflected at the glass-air boundary. A liquid is then poured on top of the glass.
What is the largest index of refraction that the liquid could have such that the ray is still totally internally reflected? The index of refraction of glass is 1.50.
Physics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

n₂ = 1.15

Explanation:

Given,

Angle of incidence,θ₁ = 50°

refractive index of the glass,n₁ = 1.50

refractive index of liquid = ?

For largest refractive index angle of refraction should be equal to 90°.

Using Snell's law

n₁ sin θ₁ =  n₂ sin θ₂

1.50 x sin 50° =  n₂ sin 90°

n₂ = 1.15

Hence, refractive index of the liquid is equal to 1.15.

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A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are
RSB [31]

Answer: 6.125 ft

Explanation:

If this dish has the form of a concave upward parabola and its vertex p is at the origin, its corresponding equation is:

x^{2}=4py

Where:

x is the radius, which can be found by dividing the diameter d=14 ft by half. Hence x=\frac{d}{2}=\frac{14 ft}{2}=7 ft

y=2 ft is the depth

p is the vertex of the parabola, where its base is

Finding p:

p=\frac{x^{2}}{4y}

p=\frac{(7 ft)^{2}}{4(2 ft)}

Finally:

p=6.125 ft This is where the the receiver should be placed

3 0
3 years ago
PLEASE HELP! Explain how energy travels outward from the core and is emitted from the Sun. Include what happens in each layer of
xxMikexx [17]
Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
8 0
3 years ago
Read 2 more answers
A 0.35-kgkg cord is stretched between two supports, 7.4 mm apart. When one support is struck by a hammer, a transverse wave trav
Agata [3.3K]

Answer:

The tension in the string is T = 1.49*10^{-6}N.

Explanation:

For a string with tension T and linear density \mu_d carrying a transverse wave at speed v it is true that

v = \sqrt{\dfrac{T}{\mu_d} }

solving for T we get:

T = \dfrac{v^2}{\mu_d}.

Now, the transverse wave covers the distance of 7.4mm in 0.88s, which means it's speed is

v =\dfrac{7.4*10^{-3}m}{0.88s} \\\\v = 8.4*10^{-3}s

And it's linear density (mass per unit length) is

\mu_d = \dfrac{0.35kg}{7.4*10^{-3}m} \\\\\mu_d = 47.3kg/m

Therefore, the tension in the cord is

T = \dfrac{(8.4*10^{-3}m/s^2)^2}{47.3kg/m}.

\boxed{T = 1.5*10^{-6}N}

or in micro newtons

T =1.5\mu N

4 0
3 years ago
Com que rapidez estará sendo feito trabalho elétrico num resistor de 10 ohms, percorrido por uma corrente elétrica de 5 A? Qual
34kurt

Poder = (resistencia) x (corrente)²

Poder = (10 ohms) x (5 A)²

<em>Poder = 250 watts </em>(250 Joule por segundo)

2 horas = 7,200 segundos

Energia = (250 joule/seg) x (7,200 seg)

<em>Energia = 1,800,000 Joules</em>

7 0
3 years ago
In a crash test, a truck with mass 2100 kg traveling at 22 m/s smashes head-on into a concrete wall without rebounding. The fron
-BARSIC- [3]

Answer:

a) 11 m/s

b) 0.0564 s

Explanation:

Given:

m = 2100 kg

vi = 22 ..... m/s before collision

vf = 0 ......after collision to stop

Δs = 0.62   distance traveled after collision .. crumpling of truck

Part a

V_{avg} = \frac{vi- vf}{2}\\\\V_{avg} = \frac{22- 0}{2}\\\\ V_{avg} = 11 m/s

Part b

vf = vi + a*t\\vf^2 = vi^2 + 2*a*s\\\\0 = 22 + a*t\\t = -22 /a\\\\0 = 484 +2*a*(0.62)\\a = - 390.3232 m/s^2\\\\t = -22/(-390.3232)\\\\t = 0.0564 s

7 0
3 years ago
Read 2 more answers
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