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lisov135 [29]
4 years ago
7

A light ray travels inside a horizontal plate of glass, striking its upper surface at an angle of incidence of 50°. This ray is

totally internally reflected at the glass-air boundary. A liquid is then poured on top of the glass.
What is the largest index of refraction that the liquid could have such that the ray is still totally internally reflected? The index of refraction of glass is 1.50.
Physics
1 answer:
MAXImum [283]4 years ago
5 0

Answer:

n₂ = 1.15

Explanation:

Given,

Angle of incidence,θ₁ = 50°

refractive index of the glass,n₁ = 1.50

refractive index of liquid = ?

For largest refractive index angle of refraction should be equal to 90°.

Using Snell's law

n₁ sin θ₁ =  n₂ sin θ₂

1.50 x sin 50° =  n₂ sin 90°

n₂ = 1.15

Hence, refractive index of the liquid is equal to 1.15.

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Which statement best explains the relationship between the electric force between two charged objects and the distance between t
spin [16.1K]
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
3 0
4 years ago
Suppose a hydrogen atom in its ground state moves 130 cm through and perpendicular to a vertical magnetic field that has a magne
blagie [28]

Answer:a)1.11×10^-21Nm

b) 1.16×10^-3m

Explanation:see attachment

5 0
4 years ago
At the bottom of a large cylindrical tank filled with fresh water the gauge pressure is 11.6 psi. What is the height (in feet) o
Art [367]

Answer:

8.19m

Explanation:

Parameters given:

Pressure, P= 11.6 psi = 79979.185 Pa

Gauge pressure is given as:

P = h*d*g

=> h = P/(d*g)

Where

h = height of tank

d = density

g = acceleration due to gravity

Density of water = 997 kg/m³

Therefore, the height of the tank is:

h = 79979.185/(997 * 9.8)

h = 8.19m

3 0
3 years ago
Help me on question 3 pls I’m giving out brainlest
emmasim [6.3K]

Answer:

Its 150?

Explanation:

5³= 5×5×5

I hope its help :)

3 0
3 years ago
An ice cube of mass 50.0 gg can slide without friction up and down a 25.0 degreedegree slope. The ice cube is pressed against a
kompoz [17]

<em>We have assumed the distance to be 0.1 meters (not millimeters) since the question has issues when expressing the units</em>

Answer:

d=0.60\ m

Explanation:

<u>Energy Conversion</u>

We need to understand and apply the concepts of energy conversion to solve this problem. Three types of energy are manifested in the motion of the ice cube of mass m.

When it's above the ground level at a height h, it has potential gravitational energy, given by

U=mgh

If the cube is moving at speed v, it has kinetic energy, given  by

\displaystyle K=\frac{1}{2}mv^2

Finally,  when it compresses the spring, it has elastic energy:

\displaystyle E=\frac{1}{2}kx^2

Where x is the distance of compression and k is the spring constant

When the ice cube is released, it has potential gravitational energy which magnitude we cannot calculate since we don't have the height. Then it goes down the slope and acquires speed and kinetic energy until it stops when compressing the spring a distance x. In that very moment, the total energy is stored in its elastic form:

\displaystyle E=\frac{1}{2}25\cdot 0.1^2=0.125\ J

When the ice cube travels up powered by that energy, it has both kinetic and potential energies, and it stops up in the ramp and starts reversing direction when it runs out of speed, thus the total potential energy is

mgh=0.125\ J

Solving for h, knowing m=50 g=0.05 Kg

\displaystyle h=\frac{0.125}{mg}=\frac{0.125}{0.05\cdot 9.8}=0.26\ m

The height and the distance traveled in the slope d are related by

h=d.sin25^o

Thus

\displaystyle d=\frac{h}{sin25^o}=\frac{0.26}{sin25^o}=0.60\ m

\boxed {d=0.60\ m}

4 0
4 years ago
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