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Tju [1.3M]
3 years ago
12

We cannot consider something to be work unless

Physics
2 answers:
iren [92.7K]3 years ago
5 0
<span>force applied causes movement of an object in the same direction as the applied force.</span>
kari74 [83]3 years ago
5 0

Explanation:

The product of applied force and the displacement is called the amount of work done by an object. For the work to be done the force and the displacement are two important factors. The mathematical expression for the work done is given by :

W=Fd\ cos\theta

Where

\theta is the angle between applied force and the displacement

When \theta=90, W = 0

\theta=0, W = F d

\theta=180, W = -F d

So, we cannot consider something to be work unless force applied causes movement of an object in the same direction as the applied force. Hence, this is the required solution.

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Human reaction times are worsened by alcohol. How much further (in feet) would a drunk driver's car travel before he hits the br
sweet-ann [11.9K]

Answer:

A drunk driver's car travel 49.13 ft further than a sober driver's car, before it hits the brakes

Explanation:

Distance covered by the car after application of brakes, until it stops can be found by using 3rd equation of motion:

2as = Vf² - Vi²

s = (Vf² - Vi²)/2a

where,  

Vf = Final Velocity of Car = 0 mi/h

Vi = Initial Velocity of Car = 50 mi/h

a = deceleration of car  

s = distance covered

Vf, Vi and a for both drivers is same as per the question. Therefore, distance covered by both car after application of brakes will also be same.

So, the difference in distance covered occurs before application of brakes during response time. Since, the car is in uniform speed before applying brakes. Therefore, following equation shall be used:

s = vt

FOR SOBER DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 0.33 s

s = s₁

Therefore,

s₁ = (73.33 ft/s)(0.33 s)

s₁ = 24.2 ft

FOR DRUNK DRIVER:

v = (50 mi/h)(1 h/ 3600 s)(5280 ft/mi) = 73.33 ft/s

t = 1 s

s = s₂

Therefore,

s₂ = (73.33 ft/s)(1 s)

s₂ = 73.33 ft

Now, the distance traveled by drunk driver's car further than sober driver's car is given by:

ΔS = s₂ - s₁

ΔS = 73.33 ft - 24.2 ft

<u>ΔS = 49.13 ft</u>

6 0
3 years ago
Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both
o-na [289]

Answer:

-True  - True  - true   - false -false - false

Explanation:

  • True The flow depends only on the charge into the surface, not on the relative position
  • True The two vectors are radial, so their relative direction  do not changes
  • True It just depends on the charge inside
  • False, it only depends on the charge, not on the form from the integration surface
  • False, because if it has a load inside it can be considered in the center, but if the load is outside the flow lines change direction with respect to the surface
  • False The flow depends only on the load inside, not on its position
7 0
2 years ago
A black squirrel is sitting on the ground. A red squirrel is sitting on a tree branch high above the black squirrel. Both squirr
labwork [276]

The black squirrel has zero kinetic energy (if it's not moving) and lower gravitational potential energy than the red squirrel or zero gravitational potential energy if the ground is assumed to be zero gravitational potential line.

4 0
3 years ago
Read 2 more answers
Do you think a moving skateboard has energy? Why or Why not? What about a skateboard that is not moving?
puteri [66]

Answer:

Yes

Explanation:

Because if you push it, the skateboard has kinetic/potential energy.

3 0
2 years ago
Read 2 more answers
The energy transfer diagram represents the energy of a person diving into a pool.
GREYUIT [131]
The answer is A) 1000 J
According to the law of conservation of energy, the total energy before an action is always equal to the total energy after the action.
So that is, the total energy is 8000J found as potential energy, 7000J has transformed into kinetic energy, then the thermal energy should be the remaining 1000J.

Hope this helps.
6 0
3 years ago
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