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Tju [1.3M]
3 years ago
12

We cannot consider something to be work unless

Physics
2 answers:
iren [92.7K]3 years ago
5 0
<span>force applied causes movement of an object in the same direction as the applied force.</span>
kari74 [83]3 years ago
5 0

Explanation:

The product of applied force and the displacement is called the amount of work done by an object. For the work to be done the force and the displacement are two important factors. The mathematical expression for the work done is given by :

W=Fd\ cos\theta

Where

\theta is the angle between applied force and the displacement

When \theta=90, W = 0

\theta=0, W = F d

\theta=180, W = -F d

So, we cannot consider something to be work unless force applied causes movement of an object in the same direction as the applied force. Hence, this is the required solution.

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Mrac [35]

The precision (relative error) of the centripetal force is 1%.

<h3>Relative error</h3>

This is the error in measurement of a variable obtained in comparison with other variables.

F = mv²/r

where;

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F/m = v²/r

F/m = (0.01v)²/(0.01r)

F/m = 0.01v²/r

F/m = 1%(v²/r)

Thus, the precision (relative error) of the centripetal force is 1%.

Learn more about relative error here: brainly.com/question/13370015

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3 years ago
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Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

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time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

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Answer:

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Explanation:

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Speed measured at that uncertainty (v) = 92km/h

Percent uncertainty (p) is given as the ratio of the uncertainty to the speed measured then multiplied by 100%. i.e

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p = \frac{2.5}{92} * 100%

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Therefore, the percent uncertainty is 2.7%

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3 years ago
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