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Tju [1.3M]
3 years ago
12

We cannot consider something to be work unless

Physics
2 answers:
iren [92.7K]3 years ago
5 0
<span>force applied causes movement of an object in the same direction as the applied force.</span>
kari74 [83]3 years ago
5 0

Explanation:

The product of applied force and the displacement is called the amount of work done by an object. For the work to be done the force and the displacement are two important factors. The mathematical expression for the work done is given by :

W=Fd\ cos\theta

Where

\theta is the angle between applied force and the displacement

When \theta=90, W = 0

\theta=0, W = F d

\theta=180, W = -F d

So, we cannot consider something to be work unless force applied causes movement of an object in the same direction as the applied force. Hence, this is the required solution.

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How much heat must be removed from 456 g of water at 25.0°C to change it into ice at - 10.0°C?
Svet_ta [14]

Answer:

229,098.96 J

Explanation:

mass of water (m) = 456 g = 0.456 kg

initial temperature (T) = 25 degrees

final temperature (t) = - 10 degrees

specific heat of ice = 2090 J/kg

latent heat of fusion =33.5 x 10^(4) J/kg

specific heat of water = 4186 J/kg

for the water to be converted to ice it must undergo three stages:

  • the water must cool from 25 degrees to 0 degrees, and the heat removed would be Q = m x specific heat of water x change in temp

        Q = 0.456 x 4186 x (25 - (-10)) = 66808.56 J

  • the water must freeze at 0 degrees, and the heat removed would be Q = m x specific heat of fusion x change in temp

         Q = 0.456 x 33.5 x 10^(4) = 152760 J

  • the water must cool further to -10 degrees from 0 degrees, and the heat removed would be Q = m x specific heat of ice x change in temp

        Q = 0.456 x 2090 x (0 - (-10)) = 9530.4 J

The quantity of heat removed from all three stages would be added to get the total heat removed.

Q total = 66,808.56 + 152,760 + 9,530.4 = 229,098.96 J

6 0
3 years ago
Assume a reaction takes 7.5 moles of anhydrous calcium chloride and energy transfer occurs, which we record as 21.2 joules of en
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Answer: 2.83 J/mol

Explanation:

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Total energy used = 21.2 J

Heat of solution = q/n where

q = total energy

n = number of moles

Heat of solution = 21.2 / 7.5

Heat of solution = 2.83 J/mol

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