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podryga [215]
3 years ago
9

Write down the equation for the stoichiometric combustion of ethane (C2H6) with oxygen, and determine the stoichiometric air fue

l mass ratio. Atomic weights: H=1, C=12, O=16 (all kg/kmol), Air composition: 23.3% oxygen, 76.7% nitrogen (by mass).
Engineering
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

Equation:

\text{C}_{2} \text{H}_{6} + \dfrac{7}{2}\text{O}_{2} \rightarrow 2\text{CO}_{2} + 3\text{H}_{2}\text{O}

Supose we have 1 kmol of ethane, according to the equation we should have 7/2 kmol of oxygen, witch corresponds to a number of mols of air of:

0.233\text{N}_{air} = 7/2

\text{N}_{air} = 15,0 \text{kmol} [\tex]As molar weight of ethane is [tex]\dfrac{M_{air}}{M_{ethane}} = \dfrac{N_{air}\cdot MW_{air}}{N_{ethane}\cdot MW_{etane}} = \dfrac{15kmol\cdot 28.9kg/kmol}{1kmol\cdot 30kg/kmol}=14.45 and air is 0.233*32 + 0.767*28 = 28.9kg/kmol, the mass ratio is:

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Answer:

Java program is given below. You can get .class after you execute java programs, You can attach those files along with .java classes given , Those .class files are generated ones.

Explanation:

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private int y;

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// returns the fields' values

public int getX()

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public int getY()

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return y;

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public int getWidth()

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return width;

}

public int getHeight()

{

return height;

}

// returns a string such as “Coordinate is (5,12) and dimension is 4x8” where 4 is width and 8 is height. public String toString()

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======================

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========================================================================================

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