Answer:
b is the answer
Explanation:
after things are used don't they get replaced
Answer:
The code will be:
#include <stdio.h>
#include <stdlib.h>
main () {
double weight, shippingCharge, rate, segments;
int distance;
printf("Enter the weight: \n");
scanf("%lf", &weight);
printf("Enter the distance: \n");
scanf("%i", &distance);
if (weight <= 10) {
printf("Rate is $3.00 \n");
rate = 3;
} else {
printf("Rate is $5.00 \n");
rate = 5;
}
if (distance % 500 == 0) {
segments = distance / 500;
} else {
segments = distance / 500 + 1;
}
shippingCharge = rate * segments;
if (distance >1000) {
shippingCharge = shippingCharge + 10;
}
printf("Your shipping charge is $%lf\n", shippingCharge);
system ("pause");
}
Answer:
a mass of water required is mw= 1273.26 gr = 1.27376 Kg
Explanation:
Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:
Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L
where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation
therefore
mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )
replacing values
mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg
Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
