If a ball is dropped from a height its velocity will increase until it hits the ground, assuming that aerodynamic drag due to th
1 answer:
Answer:
g = 9.69 m/s²
Explanation:
given,
height from where ball is dropped = 800 cm = 8 m
impact velocity = 41 ft/s = 41 × 0.3048 = 12.45 m/s
acceleration due to gravity = ?
initial potential energy is given by
PE = m g h
= m g × 8
= 8 mg..............(1)
now final kinetic energy
=77.50 m.....................(2)
comparing equation (1) to (2)
8 mg = 77.50 m
g = 77.5/8
g = 9.69 m/s²
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Answer:
critical stress required for the propagation is 27.396615 × N/m²
Explanation:
given data
specific surface energy = 0.90 J/m²
modulus of elasticity E = 393 GPa = 393 × N/m²
internal crack length = 0.6 mm
to find out
critical stress required for the propagation
solution
we will apply here critical stress formula for propagation of internal crack
( σc ) = .....................1
here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm = 0.3 × m
so now put value in equation 1 we get
( σc ) =
( σc ) =
( σc ) = 27.396615 × N/m²
so critical stress required for the propagation is 27.396615 × N/m²
Answer:
The nail exerts a force of 573.88 Pounds on the Hammer in positive j direction.
Explanation:
Since we know that the force is the rate at which the momentum of an object changes.
Mathematically
The momentum of any body is defines as
In the above problem we see that the moumentum of the hammer is reduced to zero in 0.023 seconds thus the force on the hammer is calculated using the above relations as