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aliina [53]
3 years ago
15

HELP!! I NEED AN ANSWER!!

Chemistry
1 answer:
Ksju [112]3 years ago
6 0
Both are made of the same type of atoms
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To which factor can the principles of Nicholas Steno be applied?
Tcecarenko [31]

Answer:

the rock layers of the Grand Canyon

Explanation:

Steno's law are laws that applied to sedimentary rocks. These laws helps in understanding sedimentary sequences.

Sedimentary rocks are derived from the deposition of pre-existing rocks in basins. In order to understand some important relationships between these rock layers, Steno's  law offer a good insight.

Steno's law are often applied when we want to do relative dating of rock layers. Some of the laws are:

  • Law of superposition of strata
  • Law of original horizontality
  • Law of lateral continuity
  • Law of inclusion
  • Law of fossil and fauna succession

These laws helps to interpret sedimentary rock sequences better.

7 0
4 years ago
Read 2 more answers
Is the method for converting molecules to moles the same as that for atoms?
arlik [135]

Answer:

One mole is the Avogadro's number of particles (atoms, molecules, ions or electrons) in a substance. Converting to moles is fairly easy because the conversion is always the same.

8 0
3 years ago
H2O has a mc021-1.jpgHvap = 40.7 kJ/mol. What is the quantity of heat that is released when 27.9 g of H2O condenses?
jekas [21]
The molecular weight of H2O is 18g/mol.
Therefore, 27.9 g H2O / (1mol/18g) = 0.155 mol H2O
Calculating only for the latent heat, the heat required to be released for this amount of H2O to condense is:
40.7 kJ/mol (0.155 mol) = 6.3 kJ or -6.3 kJ since it is to be released
8 0
3 years ago
Read 2 more answers
In the following table, all the columns for the element beryllium are filled out correctly.
scoundrel [369]
That is false..........
6 0
4 years ago
Since climte is hard to study on a global scale scientists use computer models to make climate predctions?
sergeinik [125]

<u>True,</u> <em>scientists take all the numbers and </em>

<em>bring them down to a smaller scale.</em>

<em> Or in your case a smaller model.</em>

5 0
3 years ago
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