The partial pressure of gas C is 0.902 atm
calculation
partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]
percent by volume of gas C= 22%
Total percent = 36% +42% + 22% = 100 %
Total pressure = 4.1 atm
partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm
Answer:
Subtract The <u>mean</u> from each Numbers Given
Hope it helpz!
CaO because oxygen have 2 dots and calcium as well
(oxygen valency -2
calcium valncy +2)= CaO
The volume increases when the balloon temperature increases.
<u>Explanation:</u>
-10 F is converted into Kelvin as 249 K.
0°C is nothing but 0+ 273 = 273 K
And the room temperature is 25°C which is converted into Kelvin as 273 + 25 = 298 K.
249 K is below room temperature.
As per the Charles' law volume and temperature are directly proportional to each other, when the pressure of the gas remains constant.
V ∝ T
As the balloon temperature increases, the volume also increases.
<span>Tf is the freezing point of the solution(the solvent plus solute).
T*f is the freezing point of the pure solvent(without solute)
i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1.
Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol.
Tf is -1.58 Degree C</span>
