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gogolik [260]
3 years ago
12

The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w

hat is the partial pressure of gas c?
Chemistry
2 answers:
Natali [406]3 years ago
3 0

 The  partial  pressure of  gas C  is 0.902  atm


  calculation

partial pressure of gas c  =[( percent by volume of  gas   C /  total  percent)   x total pressure]


percent  by  volume of gas C= 22%

Total   percent  = 36% +42%  + 22%  = 100 %

Total  pressure  =  4.1 atm


partial  pressure  of gas C  is therefore =  22/100 x 4.1 atm = 0.902  atm

dimaraw [331]3 years ago
3 0
The total pressure of the mixture of the gases is calculated by adding up the products of the volume of the percentages with the pressure that is called the partial pressure of the component. 

For gas C, the partial pressure can be calculated through the equation,
                              Partial pressure = (0.22)(4.1 atm)
                               partial pressure = 0.902 atm

<em>ANSWER: 0.902 atm</em>
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