Question

The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, what is the partial pressure of gas c?

Answer 1

 The  partial  pressure of  gas C  is 0.902  atm

  calculation

partial pressure of gas c  =[( percent by volume of  gas   C /  total  percent)   x total pressure]

percent  by  volume of gas C= 22%

Total   percent  = 36% +42%  + 22%  = 100 %

Total  pressure  =  4.1 atm

partial  pressure  of gas C  is therefore =  22/100 x 4.1 atm = 0.902  atm

Answer 2

The total pressure of the mixture of the gases is calculated by adding up the products of the volume of the percentages with the pressure that is called the partial pressure of the component. 

For gas C, the partial pressure can be calculated through the equation,
                              Partial pressure = (0.22)(4.1 atm)
                               partial pressure = 0.902 atm

ANSWER: 0.902 atm