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satela [25.4K]
2 years ago
14

During which phase of mitosis does the cell begin to split into two daughter cells

Chemistry
2 answers:
sammy [17]2 years ago
6 0

Answer:

Telophase

Explanation:

Telophase is the last phase of mitosis. More specifically 'cytokinesis' is the division of cytoplasm and cell into two. Thus it can be included in the telophase stage as well.

artcher [175]2 years ago
3 0

Answer:

\text{Telophase}

Explanation:

<em>Telophase is the process that separates the duplicated genetic material carried in the nucleus of a parent cell into two identical daughter cells.</em>

<em />

<em />-TheAnimeGirl-<em />

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A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?
Leno4ka [110]

Answer : The volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K

Putting values in above equation, we get:

\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L

Therefore, the volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

3 0
3 years ago
Can someone help me!
Art [367]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0
Semmy [17]

Answer:

The answer would be C 214g

Explanation:

890j of heat causes 4.6°c increase in temperature

specific heat of aluminium after is o.9022 j /g°c

now by using the formula .The mass of aluminium would be c that is 214 g

7 0
2 years ago
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
1 year ago
HELP ASAP WILL MARK BRAINLIEST: How many grams of aluminum can be extracted from 5000g of alumina
Lesechka [4]

The grams of aluminium extracted from 5000g of alumina is 2647 grams

<h3>Chemical formula of alumina:</h3>
  • Al₂O₃

Let's calculate the molecular mass of Al₂O₃

Al₂O₃ = 27 × 2 + 16 × 3 = 54 + 48 = 102 g/mol

Therefore,

102 g of Al₂O₃ = 54 g of aluminium  

5000g of Al₂O₃  = ?

mass of aluminium produced = 5000 × 54 / 102

mass of aluminium produced = 270000 / 102

mass of aluminium produced  = 2647.05882353

mass of aluminium produced  = 2647 grams

learn more on mass here: brainly.com/question/14627327

4 0
2 years ago
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