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Leona [35]
2 years ago
10

In what state of matter is carbon dioxide normally found on Earth?​

Chemistry
1 answer:
nirvana33 [79]2 years ago
3 0

Answer:

Gas

Explanation:

I believe that it is usually a gas on Earth.

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What do you mean by environment conservation?​
BARSIC [14]

Explanation:

Environment conservation is an umbrella term that defines anything we do to protect our planet and conserve its natural resources so that every living thing can have an improved quality of life. bolivianouft and 7 more users found this answer helpful.

3 0
2 years ago
2
son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

8 0
3 years ago
Is the electrolysis of water an oxidation-reduction reaction??
QveST [7]

Answer:

Yes

Explanation:

Electrolysis is an example of redox reaction because reduction takes place at cathode and oxidation takes place at anode and both of these reactions take place simultaneously.

8 0
3 years ago
The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.
inessss [21]
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
8 0
2 years ago
Determine the heat of reaction for the process TiO2(s) + 4HCl(g) TiCl4(l) + 2H2(g) + O2(g) using the information given below: Ti
Aleks [24]

Answer : The heat of reaction for the process is, 1374.7 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The main chemical reaction is,

TiO_2(s)+4HCl(g)\rightarrow TiCl_4(l)+2H_2(g)+O_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) Ti(s)+O_2(g)\rightarrow TiO_2(s)     \Delta H_1=-939.7kJ

(2) 2HCl(g)\rightarrow H_2(g)+Cl_2(g)    \Delta H_2=-184.6kJ

(3) Ti(s)+2Cl_2(g)\rightarrow TiCl_4(l)    \Delta H_3=-804.2kJ

We reversing reaction 1, 3 and multiplying reaction 2 by 2 and then adding all the equations, we get :

(1) TiO_2(s)\rightarrow Ti(s)+O_2(g)     \Delta H_1=939.7kJ

(2) 4HCl(g)\rightarrow 2H_2(g)+2Cl_2(g)    \Delta H_2=2\times (-184.6kJ)=-369.2kJ

(3) TiCl_4(l)\rightarrow Ti(s)+2Cl_2(g)    \Delta H_3=804.2kJ

The expression for heat of reaction for the process is:

\Delta H_{rxn}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H_{rxn}=(939.7kJ)+(-369.2kJ)+(804.2kJ)

\Delta H_{rxn}=1374.7kJ

Therefore, the heat of reaction for the process is, 1374.7 kJ

3 0
3 years ago
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