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IrinaK [193]
3 years ago
6

Solve for x in the triangle. Round your answer to the nearest tenth.

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Check the picture below.

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A rectangular prism has a length of 4 in., a width of 2 in., and a height of 212 in.
snow_lady [41]

Answer:

V = 1696 in3

Step-by-step explanation:

your asking how many cubes are needed to fill the rectangle which just means your asking for the volume, if you multiply L*W*H you'll get the answer

hope that helps

8 0
3 years ago
Please help stupidboythink or anybody
SashulF [63]

Answer: what's the question?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
4 years ago
Read 2 more answers
Castel and Kali are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of
True [87]

Answer:

Plain is $7 and Holiday is $15

Step-by-step explanation:

Castel: 2p + 5h = 89

Kali: 9p + 10h = 213

Double Castel's: 4p + 10h = 178

Subtract fro Kali's   9p + 10h = 213

                              - 4p + 10h = 178

5p = 35

p = 7  Plain is $7

Substitute 7 into one of the equations and solve for h:

2(7) + 5h = 89

14 + 5h = 89

5h = 75

h = 15  Holiday is $15

6 0
3 years ago
Mar 01, 2:2
vredina [299]

Answer:

put it this way 10% Is 9600 and 1% is 960

Step-by-step explanation:

so if it stacks monthly you can find your answer

also if you lookup compound interest calculator it will help you will future problems

5 0
3 years ago
Read 2 more answers
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