Solve for x in the triangle. Round your answer to the nearest tenth.

A tin has asquare base whose sides measures 32 cm .the vertical sides are 50cm high.cake mixture is poured into the tin and leve

zepelin [54]

Answer:

(a) V = 51200 cubic cm

(b) V' = 38912 cubic cm

(c) V'' = V - V' = 12288 cubic cm

Step-by-step explanation:

side of the square base, s = 32 cm

height, h = 50 cm

height of cake mixture, h' = 38 cm

(a) The capacity of the tin is the volume.

Capacity of tin, V = s x s x h = 32 x 32 x 50 = 51200 cubic cm

(b) The volume of the cake mixture is

V' = s x s x h'

V' = 32 x 32 x 38 = 38912 cubic cm

(c) Volume of unoccupied space is

V'' = V - V' = 51200 - 38912 = 12288 cubic cm

6 0

3 years ago

PLEASE HELP PLZZZZZ

Hoochie [10]

The answer would be B. the square root of 5 is 2.2360679775 which is the smallest number.

4 0

3 years ago

Help I need this ASAP

ddd [48]

Answer:

1. 7:1

2. 1:8

Step-by-step explanation:

1. Start by counting the number of triangles. We see: 56 triangles. Then, count the hearts. We see: 8 hearts.

So, the ratio of triangles to hearts is 56:8 which we simplify to get: 7:1.

2. Start by adding triangles to hearts. We get: 56+8 which equals 64.

The amount of hearts equals 8 so the ratio of hearts to (hearts + triangle) is! 8:64 which equals 1:8.

4 0

3 years ago

Plssss i need help rn

wariber [46]

Answer:

3

Step-by-step explanation:

(x₁ , y₁) = (-1 , -2) & (x₂ , y₂) = (3 , 10)

$Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{10-[-2]}{3-[-1]}\\\\=\frac{10+2}{3+1}\\\\=\frac{12}{4}\\\\=4$

m = 4

y - y₁ = m (x - x₁)

y - [-2] = 4(x - [-1])

y + 2 = 4(x + 1)

y + 2 = 4x + 4

y = 4x + 4 - 2

y = 4x + 2

8 0

3 years ago

Three vertices of parallelogram WXYZ are X(–2,–3), Y(0, 5), and Z(7, 7). Find the coordinates of vertex W

Serhud [2]

The coordinates of the vertex W are (5 , -1)

Step-by-step explanation:

In the parallelogram, the diagonal bisect each other

To find a missing vertex in a parallelogram do that:

Find the mid-point of a diagonal whose endpoints are given
Use this mid-point to find the missing vertex
The mid point rule is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

∵ WXYZ is a parallelogram

∴ Its diagonals are WY and XZ

∵ The diagonal bisect each other

- That mean they have the same mid-point

∴ They intersect each other at their mid-point

∵ x = (-2 , -3) and z = (7 , 7)

∴ $x_{1}$ = -2 and $x_{2}$ = 7

∴ $y_{1}$ = -3 and $y_{2}$ = 7

- Substitute them in the rule of the mid point to find the

mid-point of XZ

∴ $M_{XZ}=(\frac{-2+7}{2},\frac{-3+7}{2})=(2.5 , 2)$

∴ The mid-point of diagonals WY and XZ is (2.5 , 2)

Let us use it to find the coordinates of vertex W

∵ W = (x , y) and Y = (0 , 5)

∴ $x_{1}$ = x and $x_{2}$ = 0

∴ $y_{1}$ = y and $y_{2}$ = 5

- Equate 2.5 by the rule of the x-coordinate of the mid-point

∵ $2.5=\frac{x+0}{2}$

- Multiply both sides by 2

∴ 5 = x + 0

∴ 5 = x

∴ The x-coordinate of point W is 5

- Equate 2 by the rule of the y-coordinate of the mid-point

∵ $2=\frac{y+5}{2}$

- Multiply both sides by 2

∴ 4 = y + 5

- Subtract 5 from both sides

∴ -1 = y

∴ The y-coordinate of point W is -1

The coordinates of the vertex W are (5 , -1)

Learn more:

You can learn more about the mid-point in brainly.com/question/10480770

#LearnwithBrainly

4 0

3 years ago