Question 2 (True/False Worth 3 points)

A gas mixture containing He, Ne, and Ar exerts a pressure of 3.00 atm. What is the partial pressure of each gas present in the m

matrenka [14]

<h3>Answer:</h3>

Partial pressure of He(P(He) = 1.5 atm.

Partial pressure of Ne(P(Ne) = 1 atm.

Partial pressure of Ar(P(Ar) = 0.5 atm.

<h3>Explanation:</h3>

According to Dalton law of partial pressure the sum of partial pressures of individual gases in a gaseous mixture is equivalent to the total pressure.

The partial pressure of a gas in a gaseous mixture is given by the product of the mole fraction and the total pressure.

Our gaseous mixture contains He, Ne, and Ar and the total pressure is 3 atm.

Since we are given the ratios of the gases in the mixture, we can calculate the partial pressure of each gas.

P(He) = 3/6 × 3 atm.

= 1.5 atm.

P(Ne) = 2/6 × 3 atm.

= 1 atm

P(Ar) = 1/6 × 3 atm.

= 0.5 atm

Therefore, the partial pressures of gases He, Ne and Ar are 1.5 atm, 1 atm, and 0.5 atm respectively.

8 0

3 years ago

IF YOU CAN HELP ME THAT WOULD BE GREAT

Likurg_2 [28]

Answer:
I. Changing the pressure:
Increasing the pressure: the amount of H₂S(g) will increase.
Decreasing the pressure: the amount of H₂S(g) will decrease.
II. Changing the temperature:
Increasing the temperature: the amount of H₂S(g) will decrease.
Decreasing the temperature: the amount of H₂S(g) will increase.
III. Changing the H₂ concentration:
Increasing the H₂ concentration: the amount of H₂S(g) will increase.
Decreasing the H₂ concentration: the amount of H₂S(g) will decrease.
Explanation:
Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
I. Changing the pressure:
When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
For the reaction: CH₄(g) + 2H₂S(g) ⇄ CS₂(g) + 4H₂(g),
The reactants side (left) has 3.0 moles of gases and the products side (right) has 5.0 moles of gases.
Increasing the pressure: will shift the reaction to the side with lower moles of gas (left side), amount of H₂S(g) will increase.
Decreasing the pressure: will shift the reaction to the side with lower moles of gas (right side), amount of H₂S(g) will decrease.
II. Changing the temperature
The reaction is endothermic since the sign of ΔH is positive.
So the reaction can be represented as:
CH₄(g) + 2H₂S(g) + heat ⇄ CS₂(g) + 4H₂(g).
Increasing the temperature:
The T is a part of the reactants, increasing the T increases the amount of the reactants. So, the reaction will be shifted to the right to suppress the effect of increasing T and the amount of H₂S(g) will decrease.
Decreasing the temperature:
The T is a part of the reactants, increasing the T decreases the amount of the reactants. So, the reaction will be shifted to the left to suppress the effect of decreasing T and the amount of H₂S(g) will increase.
III. Changing the H₂ concentration:
H₂ is a part of the products.
Increasing the H₂ concentration:
H₂ is a part of the products, increasing H₂ increases the amount of the products. So, the reaction will be shifted to the left to suppress the effect of increasing H₂ and the amount of H₂S(g) will increase.
Decreasing the H₂ concentration:
H₂ is a part of the products, decreasing H₂ decreases the amount of the products. So, the reaction will be shifted to the right to suppress the effect of decreasing H₂ and the amount of H₂S(g) will decrease.

4 0

3 years ago

12. How is the melting point of a substance related to its freezing point? Both indicate the temperature at which the solid and

krok68 [10]

Both indicate the temperature at which the solid and liquid states of a substance are in equilibrium would be your answer.

This is beacause the melting point of a substance is the same as the freezing point of a substance. At this particular temp, the substance can be either a solid or a liquid.

hope this helps!

8 0

4 years ago

Read 2 more answers

Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration on nitrate, [NO3^-], is 0.10 M. What

VikaD [51]

Answer:

The concentration of nitrate ion $NO_{3}^{-}$ is 0.033 M.

Explanation:

$Al(NO_{3})_{3} \rightarrow Al^{3+} + NO_{3}^{-}$

1 mole of $[Al^{3+}]$ = 3 mole $NO_{3}^{-}$

Let $[NO_{3}^{-}]$ = 3y

then according to above reaction,

$[Al^{3+}]$ = y

$[NO_{3}^{-}]$ = 0.10 M (given)

$[Al^{3+}]$ = ?

3y = 0.10 M

$y = \frac{0.1}{3}$

y = 0.033 M

So ,concentration of $[Al^{3+}]$ = y = 0.033 M

5 0

3 years ago

Write electron configurations for each of the following. the cations: Mg2+,Sn2+,K+,Al3+,Tl+,As3+

Eddi Din [679]

Answer:

Mg⁺² ⇒ 1s² 2s² 2p⁶

Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶

Al³⁺ ⇒ 1s² 2s² 2p⁶

Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰

As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Explanation:

The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.

Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus

Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.

In a similar fashion, the answers are:

Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰

K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶

Al³⁺ ⇒ 1s² 2s² 2p⁶

Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰

As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

3 0

3 years ago