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Kay [80]
3 years ago
12

Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe?

Chemistry
1 answer:
Pepsi [2]3 years ago
8 0

manganese The metal that is used as a sacrificial electrode to prevent the rusting of iron is manganese.

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an atom has an atomic number of 9 a mass number of 19 and an electron configuration of 2-6-1 explain why the number of electrons
sukhopar [10]
You can tell that the atom is in the excited state because:

- Electron configuration should follow the 2-8-8-2 rule, meaning that the inner shell should be filled before the next shell can start holding electrons.

- Instead of the atom's electron configuration being in the ground state at 2-8-8-1, electrons from the second shell have jumped to the third.
5 0
3 years ago
What is the molecular shape of HCN
Rufina [12.5K]
Linear Hydrogen Cyanide. In this example, HCN, the Lewis diagram shows carbon at the center with no lone electron pairs. The carbon and nitrogen are bonded through a triple bond which counts as "one electron pair". Hence the molecule has two electron pairs and is linear<span>.</span>
3 0
3 years ago
What is the mass of 0.28 mole of iron?
vredina [299]

Answer:

Your answer should be 15.68 grams.

Explanation:

Seeing as 1 mole has a mass of 56 g, 56*0.28 would get you 15.68 g.

6 0
3 years ago
Whats the formula for density? ASAP giving big points.
MakcuM [25]

Answer:

Oxygen, 43kg - Carbon, 16kg - Hydrogen, 7kg - Nitrogen, 1.8kg - Calcium, 1kg - Phosphorus, 0.78kg - Potassium, 0.14kg - Sulfur, 0.14kg - Sodium, 0.10kg - Chlorine, 0.095kg - and Magnesium, 0.019kg. 

8 0
4 years ago
Read 2 more answers
If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to
Over [174]

Answer:

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

5 0
3 years ago
Read 2 more answers
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