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wel
4 years ago
11

The number of grams per mole of something is known as?​

Chemistry
1 answer:
Whitepunk [10]4 years ago
7 0

Answer:

Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)

Let me know if my interpretation is incorrect and please tell me what you are actually trying to find.

You might be interested in
Butane is a(n) _____.
zlopas [31]
I think the correct answer would be : D) organic compound and hydrocarbon
I hope this helps !
7 0
4 years ago
Read 2 more answers
I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
Determine the concentrations of BaBr2, Ba2 , and Br– in a solution prepared by dissolving 1.38 × 10–4 g BaBr2 in 2.00 L of water
Sveta_85 [38]
The correct answer to this question is this one:

Assuming all the barium bromide dissolved (which it should), the concentration of BaBr2 in solution should be zero: it should all dissociate into Ba+2 and 2Br- ions.

Turn those grams of BaBr2 into moles of BaBr2, then divide by the volume to get the concentration.

Recognize that every formula unit of BaBr2 has one ion of Ba+2, and 2 ions of Br-1. That means that when this substance dissociates, you'll get one concentration of Ba+2 ions, and a concentration of Br- ions TWICE as large. Whatever the concentration of Ba+2 ions is that you calculate, double it for the conentration of the Br-1 ion.

4 0
3 years ago
Suppose that the microwave radiation has a wavelength of 12.4 cm . How many photons are required to heat 255 mL of coffee from 2
vivado [14]

Answer:

Explanation:

wavelength λ = 12.4 x 10⁻² m .

energy of one photon = h c / λ

= 6.6 x 10⁻³⁴ x 3 x 10⁸ /  12.4 x 10⁻²

= 1.6 x 10⁻²⁴ J .

Let density of coffee be equal to density of water .

mass of coffee = 255 x 1 = 255 g

heat required to heat up coffee = mass x specific heat x rise in temp

= 255 x 4.18 x ( 62-25 )

= 39438.3 J  .

No of photons required = heat energy required / energy of one photon

= 39438.3 / 1.6 x 10⁻²⁴

= 24649 x 10²⁴

= 24.65 x 10²⁷ .

5 0
3 years ago
The net ionic equation for the reaction between aqueous solutions of hf and koh is ________.
choli [55]

Answer:

The net ionic equation for the reaction between aqueous solutions of hf and koh is  H⁺  + OH⁻  →  H₂O (l)

Explanation:

This is the complete reaction:

HF (aq)+ KOH (aq) →  KF (aq) +  H₂O (l)

Hydrofluoric acid dissociates according to this equation:

HF → H⁺  +  F⁻

And we get protons plus fluorides.

Sodium hydroxide dissociates into:

KOH  →  K⁺  +  OH⁻

potassium cation and hydroxyls.

First of all, the aqueous compounds must be separated into their ions.

Aqueous are the only one, you can break apart.

Don't forget to establish solubility in the compounds. For this case no one is soluble in water.

We make the complete ionic equation with all the aqueous compounds:

H⁺  +  F⁻   +  K⁺  +  OH⁻  →   F⁻   +  K⁺

and afterwards, cancel the ions that are repeat on reactant and product sides. This are the spectator ions.

As we eliminate F⁻   +  K, the net ionic equation will be:

H⁺  + OH⁻  →  H₂O (l)

7 0
3 years ago
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