Question

P=16,000,r=4%,t=25 years;compounded continuously

Answer 1

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \ 16000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &25 \end{cases} \\\\\\ A=16000e^{0.04\cdot25}\implies A=16000e\implies A\approx 43492.51$