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Vinvika [58]
3 years ago
5

(HELP FAST)Which of the following always changes when a substance undergoes a chemical change?

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
7 0
I’m pretty sure it’s a
GrogVix [38]3 years ago
3 0
A- the change of matter
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what volume will it occupied 40 degrees celsius a gas sample was collected when a temperature is 27 degrees celsius and the volu
love history [14]
  • T_1=27°C
  • T_2=40°C
  • V_1=1L
  • V_2=?

Using Charles law

\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto 1(40)=27V_2

\\ \sf\longmapsto V_2=\dfrac{40}{27}

\\ \sf\longmapsto V_2=1.48\ell

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The property which primarily controls how much water can be present as a gas is:
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The question above primarily talks about humidity-the amount of water vapor in the air. As the  temperature increases, the air or gas can hold more water. The warmer the air is, the more water it can possibly hold as vapor.
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4 years ago
Gases and liquids will both expand to fill their container.<br> True<br> False ...?
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All the nonmetals have some similar physical properties.<br><br> True<br> False
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4 years ago
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The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
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