112.5 g. The production of 50.00 g O2 requires 112.5 g H2O.
a) Write the partially balanced equation for the decomposition of water.
MM = 18.02 32.00
2H2O → O2 + …
Mass/g = 50.00
b) Calculate the <em>moles of O2
</em>
Moles of O2 = 50.00 g O2 × (1 mol O2/16.00 g O2) = 3.1250 mol O2
c) Calculate the <em>moles of water</em>
Moles of H2O = 3.1250 mol O2 × (2 mol H2O/1 mol O2)
= 6.2500 mol H2O
d) Calculate the mass of water
Mass of H2O = 6.2500 mol H2O × (18.02 g H2O/1 mol H2O)
= 112.5 g H2O
Answer:
2.97 × 10¹³ g
Explanation:
First, we have to calculate the biomass the is burned. We can establish the following relations:
- 2.47 acre = 10,000 m²
- 10 kg of C occupy an area of 1 m²
- 50% of the biomass is burned
The biomass burned in the site of 400,000 acre is:

Let's consider the combustion of carbon.
C(s) + O₂(g) ⇒ CO₂(g)
We can establish the following relations:
- The molar mass of C is 12.01 g/mol
- 1 mole of C produces 1 mole of CO₂
- The molar mass of CO₂ is 44.01 g/mol
The mass of produced is CO₂:

Answer:
2.551020408163 and it keeps on going or 2 27⁄49
That would be a catalyst, it makes the reaction faster.