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Novay_Z [31]
3 years ago
11

Which of the following is true about a system at equilibrium? a The concentration(s) of the reactant(s) is equal to the concentr

ation(s) of the product(s). b No new product molecules are formed. c The concentration(s) of reactant(s) is constant over time. d The rate of the reverse reaction is equal to the rate of the forward reaction and both rates are equal to zero. e None of the above (a-d) is true.
Chemistry
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

c The concentration(s) of reactant(s) is constant over time.  

Step-by-step explanation:

When the reaction A ⇌ B reaches equilibrium, the concentrations of reactants and products are constant over time.

a is <em>wrong</em>, because the concentrations of reactants and products are usually quite different.

b is <em>wrong</em>, because both product and reactant molecules are being formed at equilibrium.

d is <em>wrong</em>. The rates of the forward and reverse reactions are equal, but they are not zero.

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Whose work directly resulted in the development of an atomic model that has negative electrons stuck within a sea of positive ma
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Explanation: It verified J. J. Thomson's work on the atomic structure.

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Four moles of hydrogen chloride (HCl) gas react with one mole of oxygen (O2) gas to produce two moles of chlorine gas (Cl2) and
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Answer:

4HCl(g) + O₂(g) →  2Cl₂(g) + 2H₂O(g)

Explanation:

In order to find the equation we should state:

The reactants → Hydrogen chloride (HCl) and oxygen (O₂)

The products → Chlorine gas (Cl₂) and water gas (H₂O)

The balanced equation is:

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Which variable is held constant when testing for the thermal expansion relationship of a gas?
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Mercury chloride is a commercial fungicide. If the molar mass is 470 g/mol and the percent composition is 85.0% Hg and 15.0% Cl,
ElenaW [278]
Data: molar mass 470 g/mol

Percent composition:

Hg = 85.0%
Cl = 15.0%

Solution:

1)  Convert % to molar ratios

A. Base: 100 g

=> Hg = 85.0 g / 200.59 g/mol = 0.4235 mol

     Cl = 15.0 g / 35.45 g/mol = 0.4231 mol

B. divide by the higher number and round to whole number

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Cl = 0.4231 / 0.4231 = 1.00

=> Empirical formula = Hg Cl

2) Find the mass of the empirical formula:

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3) Determine how many times is the empirical mass contained in the molecular mass:

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=> Molecular formula = Hg2 Cl2.

Answers:

Empirical formula HgCl
Molecular Formula Hg2Cl2
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