Answer:
Volume of NaOH required = 3.61 L
Explanation:
H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:
--------(1)
where, Ka1 = 1.5 x 10–2 or pKa1 = 1.824
--------(2)
where, Ka2 = 1.0 x 10–7 or pKa2 = 7.000
The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.
Step 1:
Based on equation(1), at the first eq point:
moles of H2SO3 = moles of NaOH

Step 2:
For the second equivalence point setup an ICE table:

Initial 1.98 ? 0
Change -x -x x
Equil 1.98-x ?-x x
Here, ?-x =0 i.e. amount of OH- = x
Based on the Henderson buffer equation:
![pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles](https://tex.z-dn.net/?f=pH%20%3D%20pKa2%20%2B%20log%5Cfrac%7B%5BSO3%5D%5E%7B2-%7D%20%7D%7B%5BHSO3%5D%5E%7B-%7D%20%7D%20%5C%5C6.247%20%3D%207.00%20%2B%20log%5Cfrac%7Bx%7D%7B%281.98-x%29%7D%20%5C%5Cx%3D0.634%20moles)
Volume of NaOH required is:

Step 3:
Total volume of NaOH required = 3.22+0.389 =3.61 L
Answer:
Sn + 4HNO3 → SnO2 + 4NO2 + 2H2O
Explanation:
The base is the species that accept hydrogen, and the acids donate hydrogen ions. Dihydrogen phosphite acts as a base and hydrosulfide sulfanide act as an acid.
<h3>What are acids and bases?</h3>
Acids are molecules or chemical species that can donate a proton or a hydrogen ion to another chemical species.
Bases are the ions or molecules that accept a proton or hydrogen ion and release a hydroxide ion.
The acid and base relationship is shown as,

Learn more about acids and bases here:
brainly.com/question/26821614
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The answer to this question would be: C) a single replacement reaction
In single replacement reaction the molecule made in just one with an element. In this case, the compound is just swapping its element with a more reactive one, results in a more stable compound.
Contrast to the single replacement reaction, double replacement reaction or metathesis is the reaction which results in two new compounds. The cation from the molecule reaction is switching with the cation from other molecules.
In contrast to the double replacement reaction,