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Rashid [163]
3 years ago
11

Objects P and Q are placed in a bowl of water. P floats and Q sinks. Which one or more of the following can be deduced from this

information? 1. Q is heavier than PII. 1 cm 3 of Q has a greater mass than 1 cm 3 of P. II. Q is denser than water, and water is denser than P. * a)l only
b)I and II only
c)II and III only
d)1, 11 and III​
Physics
1 answer:
Lady bird [3.3K]3 years ago
6 0

The correct option that can be deduced for both Object P and Q is Option b) I and II only

To solve this question correctly, we need to understand the concept of density and it relation to mass and volume.

<h3>What is Density?</h3>

Density is a physical property of an object and can be expressed by using the relation:

\mathbf{Density = \dfrac{mass}{volume}}

From the given parameters, we are being told that:

  • P → floats
  • Q → sinks

This implies that Q has a greater density that P. Since Q has a greater density than P, Q will be heavier since it will have greater mass.

However, Q will not be denser than water because if that happens, P will be have a greater density which is untrue in this scenario.

Therefore, we can conclude that:

  • 1. Q is heavier than P
  • II. 1cm³ of Q has a greater mass than 1cm³ of P

Learn more about density here:

brainly.com/question/6838128

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All atoms of the element potassium have 19 protons. One of the most stable types of potassium atoms has the mass number 39. How
nydimaria [60]
For atoms in the periodic table, the given mass number is the sum of the number of the protons (also called the atomic number) and the number of the neutrons inside its nucleus. Mathematically,
                              mass number = atomic number + number of neutrons
Substituting,
                               39 = 19  + n
                                    n = 39 - 19 = 20
Therefore, the answer is not found in the choices. 
7 0
3 years ago
Read 2 more answers
an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?
gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

F_{net} = F_g - F = m\cdot g - F\\

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N

The tension force F in the supporting cables is 7245N


3 0
4 years ago
particle of mass 59 g and charge 51 µC is released from rest when it is 32 cm from a second particle of charge −14 µC. Determine
AleksAgata [21]

Answer:

The initial acceleration of the 59g particle is 1062.7\frac{m}{s^{2}}

Explanation:

Newton's second laws relates acceleration (a), net force(F) and mass (m) in the next way:

F=ma (1)

We already know the mass of the particle so we should find the electric force on it to use on (1), the magnitude of the electric force between two charged objects by Columb's law is:

F=k\frac{\mid q_{1}q_{2}\mid}{r^{2}}

with q1 and q2 the charge of the particles, r the distance between them and k the constant k=9.0\times10^{9}\,\frac{Nm^{2}}{C^{2}}. So:

F=(9.0\times10^{9})\frac{\mid (51\times10^{-6})(-14\times10^{-6})\mid}{0.32^{2}}

F=62.7 N

Using that value on (1) and solving for a

a=\frac{F}{m}=\frac{62.7}{0.059}=1062.7\frac{m}{s^{2}}

4 0
4 years ago
A boy whirls a stone in a horizontal circle of radius 1.1 m and at height 2.1 m above ground level. The string breaks, and the s
DedPeter [7]

Answer:

212.8 m/s^{2}

Explanation:

Time taken by stone to cover horizontal distance

t=\sqrt{\frac {2h}{g}} where t is time, h is height of whirling the stone in horizontal circle, g is gravitational constant, Substituting h for 2.1 m and g for 9.81

t=\sqrt{\frac {2*2.1}{9.81}}= 0.654654 seconds

t=0.65 s

Velocity, v= distance/time

v=10/0.65= 15.27525 m/s

v=15.3 m/s

a=\frac {v^{2}}{r} where r is radius of circle, substituting r with 1.1m

a=\frac {15.3^{2}}{1.1}

a=212.8 m/s^{2}

Therefore, centripetal acceleration is 212.8 m/s^{2}

8 0
4 years ago
2. Which is a possible unit of mass?<br> gram<br> liter<br> meter
Pachacha [2.7K]

Answer:

Gram

Explanation:

Meter is a unit used to measure length and liter is used to measure liquids therefore using process of elimination the answer has to be gram

4 0
3 years ago
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