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Lana71 [14]
3 years ago
14

You discover a binary star system in which one member is a15 solar mass main-sequence star and the other star is a 10 solar mass

giant star. How do we believe that a star system such as this might have come to exist?
Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

yes

Explanation:

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lock of mass m2 is attached to a spring of force constant k and m1 . m2. If the system is released from rest, and the spring is
patriot [66]

Answer:

The maximum displacement of the mass m₂ = \frac{2(m_1-m_2)g}{k}

Explanation:

Kinetic Energy (K) = 1/2mv²

Potential Energy (P) = mgh

Law of Conservation of energy states that total energy of the system remains constant.

i.e; Total energy before collision = Total energy after collision

This implies that: the gravitational potential energy lost by m₁ must be equal to sum of gravitational energy gained by m₂ and the elastic potential energy stored in the spring.

m_1gd = m_2gd+\frac{1}{2}kd^2\\\\m_1g = m_2g+\frac{1}{2}kd\\\\d = \frac{2(m_1-m_2)g}{k}

d = maximum displacement of the mass m₂

7 0
3 years ago
The term solstice translates as "Sun stop." Explain why this translation makes sense from an astronomical point of view. It make
adoni [48]

Answer:

It makes sense because on that the day  the sun stops moving northward and starts moving southward

Explanation:

4 0
3 years ago
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What makes psychoanalysis different from behaviorism?
irakobra [83]
Psychoanalysis considers introspection and examines the subconscious.
7 0
2 years ago
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A jewellery melts 500g of Silver to pour into a mould. Calculate how much energy was released as the silver solidified.
irga5000 [103]

When silver is poured into the mould the it will solidify

In this process the phase of the Silver block will change from liquid to solid.

This phase change will lead to release in heat and this heat is known as latent heat of fusion.

The formula to find the latent heat of fusion is given as

Q = mL

here given that

m = mass = 500 g

L = 111 kJ/kg

now we can find the heat released

Q = 0.5 * 111 kJ

Q = 55.5 kJ

So it will release total heat of 55.5 kJ when it will solidify

8 0
3 years ago
A 15.7-g aluminum block is warmed to 53.2 °c and plunged into an insulated beaker containing 32.5 g of water initially at 24.5 °
ipn [44]

The equilibrium temperature of aluminium and water is 33.2°C

We know that specific heat of aluminium is 0.9 J/gm-K, and that of water is 1 J/gm-K

Now we can calculate the equilibrium temperature

(mc∆T)_aluminium=(mc∆T)_water

15.7*0.9*(53.2-T)=32.5*1*(T-24.5)

T=33.2°C

6 0
3 years ago
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