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Lana71 [14]
3 years ago
14

You discover a binary star system in which one member is a15 solar mass main-sequence star and the other star is a 10 solar mass

giant star. How do we believe that a star system such as this might have come to exist?
Physics
1 answer:
Trava [24]3 years ago
3 0

Answer:

yes

Explanation:

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What is the difference between kinetic and mechanical energy?
Wittaler [7]
Kinetic energy is energy that is in motion, thats all I remember
8 0
3 years ago
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Alexis walked 1.5 km to her house in 0.5 hours. What is Alexis’ speed?
katrin2010 [14]

Answer:

Speed = 3 [km/h]

Explanation:

To solve this problem we must use the definition of speed which relates the distance traveled for a while.

Distance = 1.5 [km] = 1500 [m].

time = 0.5 [hr] = 1800 [s]

Speed = Distance/time

Speed = 1.5/0.5

Speed = 3 [km/h] or 1500/1800 = 0.8333[m/s]

4 0
2 years ago
A hockey puck is traveling to the left with a velocity of v=10 when it is struck by the hockey stick
Lera25 [3.4K]
We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
= ( 20 * 0.766 ) i + ( 20 * 0.64278 ) j = ( 15.32 i + 12.855 j ) m/s
Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
= 15.32 i + 12.855 j + 10 i = 25.32 i + 12.855 j
| Δv | = √ ( 25.32² + 12.855²) = √806.35 = 28.4 m/s
Imp = 0.2 kg * 28.4 m/s = 5.68 N-s
Answer: D ) 5.68 N-s. 
 
4 0
3 years ago
Birdman is flying horizontally at a
zavuch27 [327]

Answer:

X=92.49 m

Explanation:

Given that

u= 21 m/s

h= 97 m

Time taken to cover vertical distance h

h= 1/2 g t²

By putting the values

97 = 1/2 x 10 x  t²          ( g = 10 m/s²)

t= 4.4 s

The horizontal distance

X= u .t

X= 21 x 4.4

X=92.49 m

3 0
3 years ago
The temperature of a 700.96 gram piece of metal falls 120⁰C and in the process releases 2001 Joules of energy. What is the speci
olga nikolaevna [1]

Answer:

The specific heat for the metal is 0.466 J/g°C.

Explanation:

Given,

Q = 1120 Joules

mass = 12 grams

T₁ = 100°C

T₂ = 300°C

The specific heat for the metal can be calculated by using the formula

Q = (mass) (ΔT) (Cp)

ΔT = T₂ - T₁ = 300°C  - 100°C   = 200°C

Substituting values,

1120 = (12)(200)(Cp)

Cp = 0.466 J/g°C.

Therefore, specific heat of the metal is 0.466 J/g°C.

8 0
3 years ago
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