Question

A 40kg-skier starts at the top of a 12-meter high slope. At the bottom, she is traveling 10 m/s. How much energy does she lose to friction
A.She doesn't lose any because mechanical energy is always conserved

B.4,704 J

C.2,000 J

D.2,704 J

Answer 1

I took this quiz the answer was D.2,704 J. Just trying to help.

Answer 2

Energy at top = U = mgh = 40 * 9.8 * 12 = 4704 J

Energy at bottom = 1/2 mv² = 1/2 * 40 * 10² = 4000 / 2 = 2000 J

Energy Lost = Final - Initial = 4704 - 2000 = 2704 J

In short, Your Answer would be Option D

Hope this helps!