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cricket20 [7]
3 years ago
5

Household current in a circuit cannot generally exceed 15 for safety reasons. What is the maximum amount of charge taht could fl

ow through this circuit in a house during the course of a 24 hour day
Physics
1 answer:
Cloud [144]3 years ago
4 0
The current I is defined as the amount of charge Q flowing through a certain point in a time t:
I= \frac{Q}{t}
which can be rewritten as 
Q=It
so, by using this formula we can calculate the maximum amount of charge that can flow in the circuit. In fact, the maximum current is I=15 A, while the time is
t=24 h=86400 s
so the maximum amount of charge is
Q=(15 A)(86400 s)=1.30 \cdot 10^6 C
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Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to str
Vlad [161]

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact is 77.19°

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

g = Acceleration due to gravity = 9.81 m/s²

u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m

The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, v_y, of the package just before landing is given by the relation;

v_y² = u² + 2·g·h

u = 0 m/s

∴ v_y² = 0 + 2×9.81×1500 = 29430 m²/s²

v_y = √29430  = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact, θ, is given as follows;

tan \theta = \dfrac{v_y}{v_x}  = \dfrac{171.55}{39.0 } = 4.4

∴ θ = tan⁻¹(4.4) = 77.19°.

6 0
3 years ago
These three bulbs are powered by the battery. What will happen if the middle light burns out? A. The two other bulbs will go out
Anna11 [10]

Answer:

C

Explanation:

4 0
3 years ago
Heat is applied to an ice cube in a closed container until only steam is present. draw a representation of this process, assumin
olga55 [171]
The solid, liquid and gas phases of water would have the same structure of the molecules since they are same substance. The only difference would be the distances of the molecules in the container. For a ice, the molecules are close to each other where the molecules vibrate only in place. For liquid, the molecules are freely moving and are at some distance with each other but not that far away with each other. Steam, on the other hand, would have molecules that are very far from each other and are freely moving in the whole container. As the container is heated, the size of the molecules would not change. It is only the volume that has changed. Also, the mass is the same since there is no outflow of the substances.
6 0
3 years ago
Glass has a _____________ index of refraction than air
rewona [7]

Glass has a <u>grater </u>index of refraction than air. The glass's and air's indexes of refraction will be 1.5 and 1, respectively.

<h3>What is an index of refraction?</h3>

The refractive index of a substance is a dimensionless quantity that specifies how quickly light passes through it in optics.

The index of refraction of the glass and air will be 1.5 and 1 respectively.

Hence,glass has a <u>grater </u>index of refraction than air.

To learn more about the index of refraction, refer to the link;

brainly.com/question/23750645

#SPJ4

4 0
2 years ago
The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 10−31 kg from rest to 3 × 107 m/s within
zaharov [31]

Answer:

Electric field, E = 40608.75 N/C

Explanation:

It is given that,

Mass of electrons, m=9.1\times 10^{-31}\ kg

Initial speed of electron, u = 0

Final speed of electrons, v=3\times 10^7\ m/s

Distance traveled, s = 6.3 cm = 0.063 m

Firstly, we will find the acceleration of the electron using third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{(3\times 10^7)^2}{2\times 0.063}

a=7.14\times 10^{15}\ m/s^2

Now we will find the electric field required in the tube as :

ma=qE

E=\dfrac{ma}{q}

E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}

E = 40608.75 N/C

So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.

3 0
2 years ago
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