Answer:
78
Step-by-step explanation:
Ed2020
The simplified rational expression is (y - 3)/(y + 3). Where y ≠ -3.
<h3>How to simplify a rational expression?</h3>
A rational expression is in the p/q form. Where p and q are polynomial functions.
To simplify this rational equation,
- Factorize the polynomials in both numerator and denomiantor.
- Cancel out common factors if any.
- If the denominator and the numerator have no common factors except 1, then that is said to be the simplest form of the given rational expression.
<h3>Calculation:</h3>
The given rational equation is
![\frac{y^2 - 12y + 27 }{y^2 - 6y - 27}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E2%20-%2012y%20%2B%2027%20%7D%7By%5E2%20-%206y%20-%2027%7D)
Factorizing the expression in the numerator:
y² - 12y + 27 = y² - 9y - 3y + 27
⇒ y(y - 9) - 3(y - 9)
⇒ (y - 3)(y - 9)
Factorizing the expression in the denominator:
y² - 6y - 27 = y² - 9y + 3y - 27
⇒ y(y - 9) + 3(y - 9)
⇒ (y + 3)(y - 9)
Since they have (y - 9) as the common factor, we can simplify,
![\frac{y^2 - 12y + 27 }{y^2 - 6y - 27}=\frac{(y-3)(y-9)}{(y+3)(y-9)}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E2%20-%2012y%20%2B%2027%20%7D%7By%5E2%20-%206y%20-%2027%7D%3D%5Cfrac%7B%28y-3%29%28y-9%29%7D%7B%28y%2B3%29%28y-9%29%7D)
⇒ (y - 3)/(y + 3) where y ≠ -3(denomiantor)
Here there are no more common factors except 1; this is the simplest form of the given rational expression.
Learn more about simplifying rational expressions here:
brainly.com/question/1928496
#SPJ9
All you can do to this expression is simplify.
You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:
![6q + 1q = 7q](https://tex.z-dn.net/?f=6q%20%2B%201q%20%3D%207q)
Therefore your end result is:
Answer:
Complementary, x=78
Step-by-step explanation:
90= (x-8)+20
complementary angles add up to 90 degrees.
Answer:
130.3 lbs
Step-by-step explanation:
Just plug in the 5.35 into the x and solve. Hope this helps :)