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MrMuchimi
3 years ago
6

A control device that uses a small input current to energize or de-energize the load connected to it.​

Physics
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

contactor

Explanation:

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An old lady sits on and pushes down on a park bench. What is the reaction force? A. The bench pushes up on her. B. The Earth pul
Vladimir [108]
B the earth pulls down because of gravity
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Answer this question if your cool, but you also gotta be smart
Volgvan

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D. Z is present outside the solar system

Explanation:

cool and smart

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3 years ago
A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s
Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

Explanation:

Given

Weight of sledge hammer = 2.30 kilogram

Speed of sledge hammer = 62.7 meter per second

Kinetic energy is equal to half the product of mass and velocity square

K E = \frac{1}{2} mv^2

Substituting the value of mass and velocity, we get -

KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

\frac{1}{4} * 4520.9835\\= 1130.246

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

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3 years ago
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An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi
shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = a^{2}

Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
4 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

where k is Coulomb's constant.

Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

F = 120.85  \ N

8 0
3 years ago
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